PPt on Functions

PPt on Functions

• 1.
  Objectives The studentwill be able to: 1. To determine if a relation is a function. 2. To find the value of a function. SOL: A.7aef Designed by Skip Tyler, Varina High School
• 2.
  Functions A function is a relation in which each element of the domain is paired with exactly one element of the range. Another way of saying it is that there is one and only one output ( y ) with each input ( x ). f ( x ) x y
• 3.
  Function Notation OutputInput Name of Function
• 4.
  Determine whether eachrelation is a function. 1. {(2, 3), (3, 0), (5, 2), (4, 3)} YES, every domain is different! f ( x ) 2 3 f ( x ) 3 0 f ( x ) 5 2 f ( x ) 4 3
• 5.
  Determine whether therelation is a function. 2. {(4, 1), (5, 2), (5, 3), (6, 6), (1, 9)} NO, 5 is paired with 2 numbers! f ( x ) 4 1 f ( x ) 5 2 f ( x ) 5 3 f ( x ) 6 6 f ( x ) 1 9
• 6.
  Is this relationa function? {(1,3), (2,3), (3,3)} Yes No Answer Now
• 7.
  Vertical Line Test(pencil test) If any vertical line passes through more than one point of the graph, then that relation is not a function. Are these functions? FUNCTION! FUNCTION! NOPE!
• 8.
  Vertical Line TestNO WAY! FUNCTION! FUNCTION! NO!
• 9.
  Is this agraph of a function? Yes No Answer Now
• 10.
  Given f(x) =3x - 2, find: 1) f (3) 2) f (-2) 3(3)-2 3 7 3(-2)-2 -2 -8 = 7 = -8
• 11.
  Given h(z) = z 2 - 4z + 9, find h (-3) (-3) 2 -4(-3)+9 -3 30 9 + 12 + 9 h(-3) = 30
• 12.
  Given g(x) =x 2 – 2, find g(4) 2 6 14 18 Answer Now
• 13.
  Given f(x) =2x + 1, find -4[f(3) – f(1)] -40 -16 -8 4 Answer Now