Fundamental Concepts
 Maximum size of the Main Memory
 byte-addressable
 CPU-Main Memory Connection
Up to 2 kaddressable
MDR
MAR
k-bit
address bus
n-bit
data bus
Control lines
( , MFC, etc.)
Processor Memory
locations
Word length = n bits
W
R /
 Measures for the speed of a memory:
 memory access time.
 memory cycle time.
 An important design issue is to provide
a computer system with as large and
fast a memory as possible, within a
given cost target.
 Several techniques to increase the
effective size and speed of the memory:
 Cache memory (to increase the effective speed).
 Virtual memory (to increase the effective size).
Semiconductor RAM memories
 Each memory cell can hold one bit of information.
 Memory cells are organized in the form of an array.
 One row is one memory word.
 All cells of a row are connected to a common line, known
as the “word line”.
 Word line is connected to the address decoder.
 Sense/write circuits are connected to the data
input/output lines of the memory chip.
FF
circuit
Sense / Write
Address
decoder
FF
CS
cells
Memory
circuit
Sense / Write Sense / Write
circuit
Data input /output lines:
A0
A1
A2
A3
W0
W1
W15
7 1 0
W
R /
7 1 0
b7 b1 b0
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
•
 Two transistor inverters are cross connected to implement a basic flip-
flop.
 The cell is connected to one word line and two bits lines by transistors
T1 and T2
 When word line is at ground level, the transistors are turned off and
the latch retains its state
 Read operation: In order to read state of SRAM cell, the word line is
activated to close switches T1 and T2. Sense/Write circuits at the
bottom monitor the state of b and b’
Y
X
Word line
Bit lines
b
T2
T1
b
 Static RAMs (SRAMs):
 Consist of circuits that are capable of retaining their state as long as
the power is applied.
 Volatile memories, because their contents are lost when power is
interrupted.
 Access times of static RAMs are in the range of few nanoseconds.
 However, the cost is usually high.

Dynamic RAMs (DRAMs):
 Do not retain their state indefinitely.
 Contents must be periodically refreshed.
 Contents may be refreshed while accessing them for reading.
 Each row can store 512
bytes. 12 bits to select a
row, and 9 bits to select a
group in a row. Total of 21
bits.
• First apply the row address,
RAS signal latches the row
address. Then apply the
column address, CAS signal
latches the address.
• Timing of the memory unit
is controlled by a
specialized unit which
generates RAS and CAS.
• This is asynchronous DRAM
Column
CS
Sense / Write
circuits
cell array
latch
address
Row
Column
latch
decoder
Row
decoder
address
4096 512 8

 

R/W
A20 9
- A8 0
-

D0
D7
RAS
CAS
 Suppose if we want to access the consecutive
bytes in the selected row.
 This can be done without having to reselect the
row.
 Add a latch at the output of the sense circuits in each row.
 All the latches are loaded when the row is selected.
 Different column addresses can be applied to select and place different
bytes on the data lines.
 Consecutive sequence of column addresses can
be applied under the control signal CAS, without
reselecting the row.
 Allows a block of data to be transferred at a much faster rate than
random accesses.
 A small collection/group of bytes is usually referred to as a block.
 This transfer capability is referred to as the
fast page mode feature.
R/ W
RAS
CAS
CS
Clock
Cell array
latch
address
Row
decoder
Row
decoder
Column Read/Write
circuits & latches
counter
address
Column
Row/Column
address
Data input
register
Data output
register
Data
Refresh
counter
Mode register
and
timing control
•Operation is directly synchronized
with processor clock signal.
•The outputs of the sense circuits are
connected to a latch.
•During a Read operation, the
contents of the cells in a row are
loaded onto the latches.
•During a refresh operation, the
contents of the cells are refreshed
without changing the contents of
the latches.
•Data held in the latches correspond
to the selected columns are transferred
to the output.
•For a burst mode of operation,
successive columns are selected using
column address counter and clock.
CAS signal need not be generated
externally. A new data is placed during
raising edge of the clock
 Memory latency is the time it takes to
transfer a word of data to or from
memory
 Memory bandwidth is the number of
bits or bytes that can be transferred in
one second.
 DDRSDRAMs
 Cell array is organized in two banks
19-bit internal chip address
decoder
2-bit
addresses
21-bit
A0
A1
A19
memory chip
A20
D31-24
D7-0
D23-16
D15-8
512K 8

Chip select
memory chip
19-bit
address
512K 8

8-bit data
input/output
Implement a memory unit of 2M
words of 32 bits each.
Use 512x8 static memory chips.
Each column consists of 4 chips.
Each chip implements one byte
position.
A chip is selected by setting its
chip select control line to 1.
Selected chip places its data on the
data output line, outputs of other
chips are in high impedance state.
21 bits to address a 32-bit word.
High order 2 bits are needed to
select the row, by activating the
four Chip Select signals.
19 bits are used to access specific
byte locations inside the selected
chip.
 Large dynamic memory systems can be
implemented using DRAM chips in a similar way to
static memory systems.
 Placing large memory systems directly on the
motherboard will occupy a large amount of space.

Also, this arrangement is inflexible since the memory system cannot be expanded easily.
 Packaging considerations have led to the
development of larger memory units known as
SIMMs (Single In-line Memory Modules) and
DIMMs (Dual In-line Memory Modules).
 Memory modules are an assembly of memory
chips on a small board that plugs vertically onto a
single socket on the motherboard.
 Occupy less space on the motherboard.
 Allows for easy expansion by replacement.
 Recall that in a dynamic memory chip, to reduce the
number of pins, multiplexed addresses are used.
 Address is divided into two parts:
 High-order address bits select a row in the array.
 They are provided first, and latched using RAS signal.
 Low-order address bits select a column in the row.
 They are provided later, and latched using CAS signal.
 However, a processor issues all address bits at the
same time.
 In order to achieve the multiplexing, memory
controller circuit is inserted between the processor
and memory.
16
Processor
RAS
CAS
R/ W
Clock
Address
Row/Column
address
Memory
controller
R/ W
Clock
Request
CS
Data
Memory
Read-Only Memories (ROMs)
 SRAM and SDRAM chips are volatile:
 Lose the contents when the power is turned off.
 Many applications need memory devices to retain
contents after the power is turned off.
 For example, computer is turned on, the operating system
must be loaded from the disk into the memory.
 Store instructions which would load the OS from the disk.
 Need to store these instructions so that they will not be lost
after the power is turned off.
 We need to store the instructions into a non-volatile memory.
 Non-volatile memory is read in the same manner as
volatile memory.
 Separate writing process is needed to place information in
this memory.
 Normal operation involves only reading of data, this type
of memory is called Read-Only memory (ROM).
 Read-Only Memory:
 Data are written into a ROM when it is manufactured.
 Programmable Read-Only Memory (PROM):
 Allow the data to be loaded by a user.
 Process of inserting the data is irreversible.
 Storing information specific to a user in a ROM is expensive.
 Providing programming capability to a user may be better.
 Erasable Programmable Read-Only Memory
(EPROM):
 Stored data to be erased and new data to be loaded.
 Flexibility, useful during the development phase of digital systems.
 Erasable, reprogrammable ROM.
 Erasure requires exposing the ROM to UV light.
 Electrically Erasable Programmable Read-Only
Memory (EEPROM):
 To erase the contents of EPROMs, they have to be exposed to ultraviolet light.
 Physically removed from the circuit.
 EEPROMs the contents can be stored and erased electrically.
 Flash memory:
 Has similar approach to EEPROM.
 Read the contents of a single cell, but write the contents
of an entire block of cells.
 Flash devices have greater density.
▪ Higher capacity and low storage cost per bit.
 Power consumption of flash memory is very low, making
it attractive for use in equipment that is battery-driven.
 Single flash chips are not sufficiently large, so
larger memory modules are implemented using
flash cards and flash drives.
 A big challenge in the design of a computer
system is to provide a sufficiently large
memory, with a reasonable speed at an
affordable cost.
 Static RAM:
 Very fast, but expensive, because a basic SRAM cell has a complex circuit
making it impossible to pack a large number of cells onto a single chip.
 Dynamic RAM:
 Simpler basic cell circuit, hence are much less expensive, but significantly
slower than SRAMs.
 Magnetic disks:
 Storage provided by DRAMs is higher than SRAMs, but is still less than what
is necessary.
 Secondary storage such as magnetic disks provide a large amount
of storage, but is much slower than DRAMs.
Processor
Primary
cache
Main
memory
Increasing
size
Increasing
speed
Magnetic disk
secondary
memory
Increasing
cost per bit
Registers
L1
Secondary
cache
L2
•Fastest access is to the data held in
processor registers. Registers are at
the top of the memory hierarchy.
•Relatively small amount of memory that
can be implemented on the processor
chip. This is processor cache.
•Two levels of cache. Level 1 (L1) cache
is on the processor chip. Level 2 (L2)
cache is in between main memory and
processor.
•Next level is main memory, implemented
as SIMMs. Much larger, but much slower
than cache memory.
•Next level is magnetic disks. Huge amount
of inexepensive storage.
•Speed of memory access is critical, the
idea is to bring instructions and data
that will be used in the near future as
close to the processor as possible.
Cache Memories
 Processor is much faster than the main
memory.
 As a result, the processor has to spend much of its time waiting while
instructions and data are being fetched from the main memory.
 Major obstacle towards achieving good performance.
 Speed of the main memory cannot be
increased beyond a certain point.
 Cache memory is an architectural
arrangement which makes the main memory
appear faster to the processor than it really is.
 Cache memory is based on the property of
computer programs known as “locality of
reference”.
 Analysis of programs indicates that many
instructions in localized areas of a
program are executed repeatedly during
some period of time, while the others are
accessed relatively less frequently.
 These instructions may be the ones in a loop, nested loop or few
procedures calling each other repeatedly.
 This is called “locality of reference”.
 Temporal locality of reference:
 Recently executed instruction is likely to be executed again very soon.
 Spatial locality of reference:
 Instructions with addresses close to a recently instruction are likely
to be executed soon.
• Processor issues a Read request, a block of words is transferred
from the main memory to the cache, one word at a time.
• Subsequent references to the data in this block of words are found
in the cache.
• At any given time, only some blocks in the main memory are held in
the cache. Which blocks in the main memory are in the cache is
determined by a “mapping function”.
• When the cache is full, and a block of words needs to be transferred
from the main memory, some block of words in the cache must be
replaced. This is determined by a “replacement algorithm”.
Cache
Main
memory
Processor
• Existence of a cache is transparent to the processor. The processor
issues Read and
Write requests in the same manner.
• If the data is in the cache it is called a Read or Write hit.
• Read hit:
 The data is obtained from the cache.
• Write hit:
 Cache has a replica of the contents of the main memory.
 Contents of the cache and the main memory may be updated
simultaneously. This is the write-through protocol.
 Update the contents of the cache, and mark it as updated by setting a
bit known as the dirty bit or modified bit. The contents of the main
memory are updated when this block is replaced. This is write-back
or copy-back protocol.
• If the data is not present in the cache, then a Read miss or Write
miss occurs.
• Read miss:
 Block of words containing this requested word is transferred from the
memory.
 After the block is transferred, the desired word is forwarded to the
processor.
 The desired word may also be forwarded to the processor as soon as it is
transferred without waiting for the entire block to be transferred. This is
called load-through or early-restart.
• Write-miss:
 Write-through protocol is used, then the contents of the main memory
are updated directly.
 If write-back protocol is used, the block containing the
addressed word is first brought into the cache. The desired word
is overwritten with new information.
• A bit called as “valid bit” is provided for each block.
• If the block contains valid data, then the bit is set to 1, else it is 0.
• Valid bits are set to 0, when the power is just turned on.
• When a block is loaded into the cache for the first time, the valid bit is set
to 1.
• Data transfers between main memory and disk occur directly bypassing the
cache.
• When the data on a disk changes, the main memory block is also updated.
• However, if the data is also resident in the cache, then the valid bit is set to
0.
• What happens if the data in the disk and main memory changes and the
write-back protocol is being used?
• In this case, the data in the cache may also have changed and is indicated
by the dirty bit.
• The copies of the data in the cache, and the main memory are different.
This is called the cache coherence problem.
• One option is to force a write-back before the main memory is updated
from the disk.
 Mapping functions determine how
memory blocks are placed in the cache.
 A simple processor example:
 Cache consisting of 128 blocks of 16 words each.
 Total size of cache is 2048 (2K) words.
 Main memory is addressable by a 16-bit address.
 Main memory has 64K words.
 Main memory has 4K blocks of 16 words each.
 Three mapping functions:
 Direct mapping
 Associative mapping
 Set-associative mapping.
Main
memory Block 0
Block 1
Block 127
Block 128
Block 129
Block 255
Block 256
Block 257
Block 4095
7 4
Main memory address
Tag Block Word
5
tag
tag
tag
Cache
Block 0
Block 1
Block 127
•Block j of the main memory maps to j modulo 128 of
the cache. 0 maps to 0, 129 maps to 1.
•More than one memory block is mapped onto the same
position in the cache.
•May lead to contention for cache blocks even if the
cache is not full.
•Resolve the contention by allowing new block to
replace the old block, leading to a trivial replacement
algorithm.
•Memory address is divided into three fields:
- Low order 4 bits determine one of the 16
words in a block.
- When a new block is brought into the cache,
the the next 7 bits determine which cache
block this new block is placed in.
- High order 5 bits determine which of the possible
32 blocks is currently present in the cache. These
are tag bits.
•Simple to implement but not very flexible.
•Main memory block can be placed into any cache
position.
•Memory address is divided into two fields:
- Low order 4 bits identify the word within a block.
- High order 12 bits or tag bits identify a memory
block when it is resident in the cache.
•Flexible, and uses cache space efficiently.
•Replacement algorithms can be used to replace an
existing block in the cache when the cache is full.
•Cost is higher than direct-mapped cache because of
the need to search all 128 patterns to determine
whether a given block is in the cache.
Main
memory Block 0
Block 1
Block 127
Block 128
Block 129
Block 255
Block 256
Block 257
Block 4095
4
Main memory address
Tag Word
12
tag
tag
tag
Cache
Block 0
Block 1
Block 127
Blocks of cache are grouped into sets.
Mapping function allows a block of the main
memory to reside in any block of a specific set.
Divide the cache into 64 sets, with two blocks per set.
Memory block 0, 64, 128 etc. map to block 0, and they
can occupy either of the two positions.
Memory address is divided into three fields:
- 6 bit field determines the set number.
- High order 6 bit fields are compared to the tag
fields of the two blocks in a set.
Set-associative mapping combination of direct and
associative mapping.
Number of blocks per set is a design parameter.
- One extreme is to have all the blocks in one set,
requiring no set bits (fully associative mapping).
- Other extreme is to have one block per set, is
the same as direct mapping.
Main
memory Block 0
Block 1
Block 63
Block 64
Block 65
Block 127
Block 128
Block 129
Block 4095
7 4
Main memory address
Tag Block Word
5
tag
tag
tag
Cache
Block 1
Block 2
Block 126
Block 127
Block 3
Block 0
tag
tag
tag
Performance considerations
 A key design objective of a computer system is to
achieve the best possible performance at the lowest
possible cost.
 Price/performance ratio is a common measure of success.
 Performance of a processor depends on:
 How fast machine instructions can be brought into the
processor for execution.
 How fast the instructions can be executed.
 Divides the memory system into a number
of memory modules. Each module has its own address buffer
register (ABR) and data buffer register (DBR).
 Arranges addressing so that successive
words in the address space are placed in
different modules.
 When requests for memory access involve
consecutive addresses, the access will be to
different modules.
 Since parallel access to these modules is
possible, the average rate of fetching words
from the Main Memory can be increased.
 Consecutive words are placed in a
module.
 High-order k bits of a memory
address determine the module.
 Low-order m bits of a memory
address determine the word
within a module.
 When a block of words is
transferred from main memory to
cache, only one module is busy at
a time.
m bits
Address in module MM address
i
k bits
Module Module Module
Module
DBR
ABR DBR
ABR ABR DBR
0 n 1
- i
k bits
0
Module
Module
Module
Module MM address
DBR
ABR
ABR DBR
ABR DBR
Address in module
2
k
1
-
mbits
•Consecutive words are located in
consecutive modules.
•Consecutive addresses can be
located in consecutive modules.
•While transferring a block of data,
several memory modules can be kept
busy at the same time.
 Hit rate
 Miss penalty
 Hit rate can be improved by increasing block size,
while keeping cache size constant
 Block sizes that are neither very small nor very large
give best results.
 Miss penalty can be reduced if load-through
approach is used when loading new blocks into
cache.
 In high performance processors 2 levels
of caches are normally used.
 Avg access time in a system with 2
levels of caches is
T ave = h1c1+(1-h1)h2c2+(1-h1)(1-h2)M
Write buffer
 Write-through:
• Each write operation involves writing to the main memory.
• If the processor has to wait for the write operation to be complete, it
slows down the processor.
• Processor does not depend on the results of the write operation.
• Write buffer can be included for temporary storage of write requests.
• Processor places each write request into the buffer and continues
execution.
• If a subsequent Read request references data which is still in the write
buffer, then this data is referenced in the write buffer.
 Write-back:
• Block is written back to the main memory when it is replaced.
• If the processor waits for this write to complete, before reading the
new block, it is slowed down.
• Fast write buffer can hold the block to be written, and the new
block can be read first.
Prefetching
• New data are brought into the processor when they are
first needed.
• Processor has to wait before the data transfer is
complete.
• Prefetch the data into the cache before they are actually
needed, or a before a Read miss occurs.
• Prefetching can be accomplished through software by
including a special instruction in the machine language
of the processor.
 Inclusion of prefetch instructions increases the length of
the programs.
• Prefetching can also be accomplished using hardware:
 Circuitry that attempts to discover patterns in
memory references and then prefetches according
to this pattern.
Lockup-Free Cache
• Prefetching scheme does not work if it stops other
accesses to the cache until the prefetch is completed.
• A cache of this type is said to be “locked” while it
services a miss.
• Cache structure which supports multiple outstanding
misses is called a lockup free cache.
• Since only one miss can be serviced at a time, a
lockup free cache must include circuits that keep
track of all the outstanding misses.
• Special registers may hold the necessary
information about these misses.
Virtual Memory
44
 Recall that an important challenge in the
design of a computer system is to provide a
large, fast memory system at an affordable
cost.
 Architectural solutions to increase the effective
speed and size of the memory system.
 Cache memories were developed to increase
the effective speed of the memory system.
 Virtual memory is an architectural solution to
increase the effective size of the memory
system.
45
 Recall that the addressable memory space
depends on the number of address bits in a
computer.
 For example, if a computer issues 32-bit addresses, the addressable memory space is 4G
bytes.
 Physical main memory in a computer is generally
not as large as the entire possible addressable
space.
 Physical memory typically ranges from a few hundred megabytes to 1G bytes.
 Large programs that cannot fit completely into the
main memory have their parts stored on
secondary storage devices such as magnetic disks.
 Pieces of programs must be transferred to the main memory from secondary storage
before they can be executed.
46
 When a new piece of a program is to be
transferred to the main memory, and the
main memory is full, then some other
piece in the main memory must be
replaced.
 Recall this is very similar to what we studied in case of cache memories.
 Operating system automatically transfers
data between the main memory and
secondary storage.
 Application programmer need not be concerned with this transfer.
 Also, application programmer does not need to be aware of the
limitations imposed by the available physical memory.
47
 Techniques that automatically move program and
data between main memory and secondary storage
when they are required for execution are called
virtual-memory techniques.
 Programs and processors reference an instruction or
data independent of the size of the main memory.
 Processor issues binary addresses for instructions
and data.
 These binary addresses are called logical or virtual addresses.
 Virtual addresses are translated into physical
addresses by a combination of hardware and
software subsystems.
 If virtual address refers to a part of the program that is currently in the main memory, it is
accessed immediately.
 If the address refers to a part of the program that is not currently in the main memory,
it is first transferred to the main memory before it can be used.
48
Data
Data
DMA transfer
Physical address
Physical address
Virtual address
Disk storage
Main memory
Cache
MMU
Processor
•Memory management unit (MMU) translates
virtual addresses into physical addresses.
•If the desired data or instructions are in the
main memory they are fetched as described
previously.
•If the desired data or instructions are not in
the main memory, they must be transferred
from secondary storage to the main memory.
•MMU causes the operating system to bring
the data from the secondary storage into the
main memory.
49
 Assume that program and data are
composed of fixed-length units called pages.
 A page consists of a block of words that
occupy contiguous locations in the main
memory.
 Page is a basic unit of information that is
transferred between secondary storage and
main memory.
 Size of a page commonly ranges from 2K to
16K bytes.
 Pages should not be too small, because the access time of a secondary
storage device is much larger than the main memory.
 Pages should not be too large, else a large portion of the page
may not be used, and it will occupy valuable space in the main memory.
50
 Concepts of virtual memory are similar
to the concepts of cache memory.
 Cache memory:
 Introduced to bridge the speed gap between the processor and the
main memory.
 Implemented in hardware.
 Virtual memory:
 Introduced to bridge the speed gap between the main memory and
secondary storage.
 Implemented in part by software.
51
 Each virtual or logical address generated by a
processor is interpreted as a virtual page
number (high-order bits) plus an offset (low-
order bits) that specifies the location of a
particular byte within that page.
 Information about the main memory location
of each page is kept in the page table.
 Main memory address where the page is stored.
 Current status of the page.
 Area of the main memory that can hold a page
is called as page frame.
 Starting address of the page table is kept in a
page table base register.
52
 Virtual page number generated by the
processor is added to the contents of
the page table base register.
 This provides the address of the corresponding entry in the page
table.
 The contents of this location in the
page table give the starting address of
the page if the page is currently in the
main memory.
53
Page frame
Virtual address from processor
in memory
Offset
Offset
Virtual page number
Page table address
Page table base register
Control
bits
Physical address in main memory
PAGE TABLE
Page frame
+
Virtual address is
interpreted as page
number and offset.
Page table holds information
about each page. This includes
the starting address of the page
in the main memory.
PTBR holds
the address of
the page table.
PTBR + virtual
page number provide
the entry of the page
in the page table.
This entry has the starting location
of the page.
54
 Page table entry for a page also includes
some control bits which describe the status
of the page while it is in the main memory.
 One bit indicates the validity of the page.
 Indicates whether the page is actually loaded into the main memory.
 Allows the operating system to invalidate the page without actually
removing it.
 One bit indicates whether the page has
been modified during its residency in the
main memory.
 This bit determines whether the page should be written back to the disk
when it is removed from the main memory.
 Similar to the dirty or modified bit in case of cache memory.
55
 Other control bits for various other
types of restrictions that may be
imposed.
 For example, a program may only have read permission for a page,
but not write or modify permissions.
56
 Where should the page table be located?
 Recall that the page table is used by the MMU for
every read and write access to the memory.
 Ideal location for the page table is within the MMU.
 Page table is quite large.
 MMU is implemented as part of the processor chip.
 Impossible to include a complete page table on the
chip.
 Page table is kept in the main memory.
 A copy of a small portion of the page table can be
accommodated within the MMU.
 Portion consists of page table entries that correspond to the most recently
accessed pages.
57
 A small cache called as Translation Lookaside
Buffer (TLB) is included in the MMU.
 TLB holds page table entries of the most recently accessed pages.
 Recall that cache memory holds most recently
accessed blocks from the main memory.
 Operation of the TLB and page table in the main memory is similar to the
operation of the cache and main memory.
 Page table entry for a page includes:
 Address of the page frame where the page resides in the main memory.
 Some control bits.
 In addition to the above for each page, TLB
must hold the virtual page number for each
page.
58
No
Yes
Hit
Miss
Virtual address from processor
TLB
Offset
Virtual page number
number
Virtual page Page frame
in memory
Control
bits
Offset
Page frame
=?
Physical address in main memory
Associative-mapped TLB
High-order bits of the virtual address
generated by the processor select the
virtual page.
These bits are compared to the virtual
page numbers in the TLB.
If there is a match, a hit occurs and
the corresponding address of the page
frame is read.
If there is no match, a miss occurs
and the page table within the main
memory must be consulted.
Set-associative mapped TLBs are
found in commercial processors.
59
 How to keep the entries of the TLB coherent
with the contents of the page table in the
main memory?
 Operating system may change the contents
of the page table in the main memory.
 Simultaneously it must also invalidate the corresponding entries in the TLB.
 A control bit is provided in the TLB to
invalidate an entry.
 If an entry is invalidated, then the TLB gets
the information for that entry from the page
table.
 Follows the same process that it would follow if the entry is not found in the
TLB or if a “miss” occurs.
60
 What happens if a program generates
an access to a page that is not in the
main memory?
 In this case, a page fault is said to occur.
 Whole page must be brought into the main memory from the disk,
before the execution can proceed.
 Upon detecting a page fault by the
MMU, following actions occur:
 MMU asks the operating system to intervene by raising an exception.
 Processing of the active task which caused the page fault is
interrupted.
 Control is transferred to the operating system.
 Operating system copies the requested page from secondary storage
to the main memory.
 Once the page is copied, control is returned to the task which was
interrupted.
61
 Servicing of a page fault requires
transferring the requested page from
secondary storage to the main memory.
 This transfer may incur a long delay.
 While the page is being transferred the
operating system may:
 Suspend the execution of the task that caused the page fault.
 Begin execution of another task whose pages are in the main memory.
 Enables efficient use of the processor.
62
 How to ensure that the interrupted task
can continue correctly when it resumes
execution?
 There are two possibilities:
 Execution of the interrupted task must continue from the point
where it was interrupted.
 The instruction must be restarted.
 Which specific option is followed
depends on the design of the processor.
63
 When a new page is to be brought into the main
memory from secondary storage, the main
memory may be full.
 Some page from the main memory must be replaced with this new page.
 How to choose which page to replace?
 This is similar to the replacement that occurs when the cache is full.
 The principle of locality of reference (?) can also be applied here.
 A replacement strategy similar to LRU can be applied.
 Since the size of the main memory is relatively
larger compared to cache, a relatively large
amount of programs and data can be held in the
main memory.
 Minimizes the frequency of transfers between secondary storage and main memory.
64
 A page may be modified during its residency
in the main memory.
 When should the page be written back to the
secondary storage?
 Recall that we encountered a similar
problem in the context of cache and main
memory:
 Write-through protocol(?)
 Write-back protocol(?)
 Write-through protocol cannot be used,
since it will incur a long delay each time a
small amount of data is written to the disk.
Memory Management
 Operating system is concerned with transferring
programs and data between secondary storage and
main memory.
 Operating system needs memory routines in
addition to the other routines.
 Operating system routines are assembled into a
virtual address space called system space.
 System space is separate from the space in which
user application programs reside.
 This is user space.
 Virtual address space is divided into one
system space + several user spaces.
 Recall that the Memory Management Unit (MMU)
translates logical or virtual addresses into physical
addresses.
 MMU uses the contents of the page table base register to
determine the address of the page table to be used in the
translation.
 Changing the contents of the page table base register can enable
us to use a different page table, and switch from one space to
another.
 At any given time, the page table base register can point
to one page table.
 Thus, only one page table can be used in the translation process at
a given time.
 Pages belonging to only one space are accessible at any
given time.
 When multiple, independent user programs coexist in
the main memory, how to ensure that one program
does not modify/destroy the contents of the other?
 Processor usually has two states of operation:
 Supervisor state.
 User state.
 Supervisor state:
 Operating system routines are executed.
 User state:
 User programs are executed.
 Certain privileged instructions cannot be executed in user
state.
 These privileged instructions include the ones which change
page table base register.
 Prevents one user from accessing the space of other users.
Secondary Storage
Disk
Disk drive
Disk controller
Sector 0, track 0
Sector 3, track n
Figure 5.30. Organization of one surface of a disk.
Sector 0, track 1
 Sector header
 Following the data, there is an error-
correction code (ECC).
 Formatting process
 Access time – seek time / rotational
delay (latency time)
 Data buffer/cache
Processor Main memory
System bus
Figure 5.31. Disks connected to the system bus.
Disk controller
Disk drive Disk drive
 Seek
 Read
 Write
 Error checking
 Redundant Array of Inexpensive Disks
 Using multiple disks makes it cheaper for
huge storage, and also possible to improve
the reliability of the overall system.
 RAID0 – data striping
 RAID1 – identical copies of data on two
disks
 RAID2, 3, 4 – increased reliability
 RAID5 – parity-based error-recovery
(a) Cross-section
Source Detector Source Detector Source Detector
No reflection
Reflection Reflection
Pit Land
0 0 0 1 0 0 0 0 1 0 0 0 1 0 0 1 0 0 1 0
(c) Stored binary pattern
Figure 5.32. Optical disk.
1
(b) Transition from pit to land
 CD-ROM
 CD-Recordable (CD-R)
 CD-ReWritable (CD-RW)
 DVD
 DVD-RAM
Figure 5.33. Organization of data on magnetic tape.
File
File
mark
mark
File
7 or 9
gap gap
File gap Record Record
Record Record
bits
•
•
•
•
•
•
•
•

computer chapter5-the memory system (1) (2).ppt

  • 1.
  • 2.
     Maximum sizeof the Main Memory  byte-addressable  CPU-Main Memory Connection Up to 2 kaddressable MDR MAR k-bit address bus n-bit data bus Control lines ( , MFC, etc.) Processor Memory locations Word length = n bits W R /
  • 3.
     Measures forthe speed of a memory:  memory access time.  memory cycle time.  An important design issue is to provide a computer system with as large and fast a memory as possible, within a given cost target.  Several techniques to increase the effective size and speed of the memory:  Cache memory (to increase the effective speed).  Virtual memory (to increase the effective size).
  • 4.
  • 5.
     Each memorycell can hold one bit of information.  Memory cells are organized in the form of an array.  One row is one memory word.  All cells of a row are connected to a common line, known as the “word line”.  Word line is connected to the address decoder.  Sense/write circuits are connected to the data input/output lines of the memory chip.
  • 6.
    FF circuit Sense / Write Address decoder FF CS cells Memory circuit Sense/ Write Sense / Write circuit Data input /output lines: A0 A1 A2 A3 W0 W1 W15 7 1 0 W R / 7 1 0 b7 b1 b0 • • • • • • • • • • • • • • • • • • • • • • • • • • •
  • 7.
     Two transistorinverters are cross connected to implement a basic flip- flop.  The cell is connected to one word line and two bits lines by transistors T1 and T2  When word line is at ground level, the transistors are turned off and the latch retains its state  Read operation: In order to read state of SRAM cell, the word line is activated to close switches T1 and T2. Sense/Write circuits at the bottom monitor the state of b and b’ Y X Word line Bit lines b T2 T1 b
  • 8.
     Static RAMs(SRAMs):  Consist of circuits that are capable of retaining their state as long as the power is applied.  Volatile memories, because their contents are lost when power is interrupted.  Access times of static RAMs are in the range of few nanoseconds.  However, the cost is usually high.  Dynamic RAMs (DRAMs):  Do not retain their state indefinitely.  Contents must be periodically refreshed.  Contents may be refreshed while accessing them for reading.
  • 9.
     Each rowcan store 512 bytes. 12 bits to select a row, and 9 bits to select a group in a row. Total of 21 bits. • First apply the row address, RAS signal latches the row address. Then apply the column address, CAS signal latches the address. • Timing of the memory unit is controlled by a specialized unit which generates RAS and CAS. • This is asynchronous DRAM Column CS Sense / Write circuits cell array latch address Row Column latch decoder Row decoder address 4096 512 8     R/W A20 9 - A8 0 -  D0 D7 RAS CAS
  • 10.
     Suppose ifwe want to access the consecutive bytes in the selected row.  This can be done without having to reselect the row.  Add a latch at the output of the sense circuits in each row.  All the latches are loaded when the row is selected.  Different column addresses can be applied to select and place different bytes on the data lines.  Consecutive sequence of column addresses can be applied under the control signal CAS, without reselecting the row.  Allows a block of data to be transferred at a much faster rate than random accesses.  A small collection/group of bytes is usually referred to as a block.  This transfer capability is referred to as the fast page mode feature.
  • 11.
    R/ W RAS CAS CS Clock Cell array latch address Row decoder Row decoder ColumnRead/Write circuits & latches counter address Column Row/Column address Data input register Data output register Data Refresh counter Mode register and timing control •Operation is directly synchronized with processor clock signal. •The outputs of the sense circuits are connected to a latch. •During a Read operation, the contents of the cells in a row are loaded onto the latches. •During a refresh operation, the contents of the cells are refreshed without changing the contents of the latches. •Data held in the latches correspond to the selected columns are transferred to the output. •For a burst mode of operation, successive columns are selected using column address counter and clock. CAS signal need not be generated externally. A new data is placed during raising edge of the clock
  • 12.
     Memory latencyis the time it takes to transfer a word of data to or from memory  Memory bandwidth is the number of bits or bytes that can be transferred in one second.  DDRSDRAMs  Cell array is organized in two banks
  • 13.
    19-bit internal chipaddress decoder 2-bit addresses 21-bit A0 A1 A19 memory chip A20 D31-24 D7-0 D23-16 D15-8 512K 8  Chip select memory chip 19-bit address 512K 8  8-bit data input/output Implement a memory unit of 2M words of 32 bits each. Use 512x8 static memory chips. Each column consists of 4 chips. Each chip implements one byte position. A chip is selected by setting its chip select control line to 1. Selected chip places its data on the data output line, outputs of other chips are in high impedance state. 21 bits to address a 32-bit word. High order 2 bits are needed to select the row, by activating the four Chip Select signals. 19 bits are used to access specific byte locations inside the selected chip.
  • 14.
     Large dynamicmemory systems can be implemented using DRAM chips in a similar way to static memory systems.  Placing large memory systems directly on the motherboard will occupy a large amount of space.  Also, this arrangement is inflexible since the memory system cannot be expanded easily.  Packaging considerations have led to the development of larger memory units known as SIMMs (Single In-line Memory Modules) and DIMMs (Dual In-line Memory Modules).  Memory modules are an assembly of memory chips on a small board that plugs vertically onto a single socket on the motherboard.  Occupy less space on the motherboard.  Allows for easy expansion by replacement.
  • 15.
     Recall thatin a dynamic memory chip, to reduce the number of pins, multiplexed addresses are used.  Address is divided into two parts:  High-order address bits select a row in the array.  They are provided first, and latched using RAS signal.  Low-order address bits select a column in the row.  They are provided later, and latched using CAS signal.  However, a processor issues all address bits at the same time.  In order to achieve the multiplexing, memory controller circuit is inserted between the processor and memory.
  • 16.
  • 17.
  • 18.
     SRAM andSDRAM chips are volatile:  Lose the contents when the power is turned off.  Many applications need memory devices to retain contents after the power is turned off.  For example, computer is turned on, the operating system must be loaded from the disk into the memory.  Store instructions which would load the OS from the disk.  Need to store these instructions so that they will not be lost after the power is turned off.  We need to store the instructions into a non-volatile memory.  Non-volatile memory is read in the same manner as volatile memory.  Separate writing process is needed to place information in this memory.  Normal operation involves only reading of data, this type of memory is called Read-Only memory (ROM).
  • 19.
     Read-Only Memory: Data are written into a ROM when it is manufactured.  Programmable Read-Only Memory (PROM):  Allow the data to be loaded by a user.  Process of inserting the data is irreversible.  Storing information specific to a user in a ROM is expensive.  Providing programming capability to a user may be better.  Erasable Programmable Read-Only Memory (EPROM):  Stored data to be erased and new data to be loaded.  Flexibility, useful during the development phase of digital systems.  Erasable, reprogrammable ROM.  Erasure requires exposing the ROM to UV light.
  • 20.
     Electrically ErasableProgrammable Read-Only Memory (EEPROM):  To erase the contents of EPROMs, they have to be exposed to ultraviolet light.  Physically removed from the circuit.  EEPROMs the contents can be stored and erased electrically.  Flash memory:  Has similar approach to EEPROM.  Read the contents of a single cell, but write the contents of an entire block of cells.  Flash devices have greater density. ▪ Higher capacity and low storage cost per bit.  Power consumption of flash memory is very low, making it attractive for use in equipment that is battery-driven.  Single flash chips are not sufficiently large, so larger memory modules are implemented using flash cards and flash drives.
  • 21.
     A bigchallenge in the design of a computer system is to provide a sufficiently large memory, with a reasonable speed at an affordable cost.  Static RAM:  Very fast, but expensive, because a basic SRAM cell has a complex circuit making it impossible to pack a large number of cells onto a single chip.  Dynamic RAM:  Simpler basic cell circuit, hence are much less expensive, but significantly slower than SRAMs.  Magnetic disks:  Storage provided by DRAMs is higher than SRAMs, but is still less than what is necessary.  Secondary storage such as magnetic disks provide a large amount of storage, but is much slower than DRAMs.
  • 22.
    Processor Primary cache Main memory Increasing size Increasing speed Magnetic disk secondary memory Increasing cost perbit Registers L1 Secondary cache L2 •Fastest access is to the data held in processor registers. Registers are at the top of the memory hierarchy. •Relatively small amount of memory that can be implemented on the processor chip. This is processor cache. •Two levels of cache. Level 1 (L1) cache is on the processor chip. Level 2 (L2) cache is in between main memory and processor. •Next level is main memory, implemented as SIMMs. Much larger, but much slower than cache memory. •Next level is magnetic disks. Huge amount of inexepensive storage. •Speed of memory access is critical, the idea is to bring instructions and data that will be used in the near future as close to the processor as possible.
  • 23.
  • 24.
     Processor ismuch faster than the main memory.  As a result, the processor has to spend much of its time waiting while instructions and data are being fetched from the main memory.  Major obstacle towards achieving good performance.  Speed of the main memory cannot be increased beyond a certain point.  Cache memory is an architectural arrangement which makes the main memory appear faster to the processor than it really is.  Cache memory is based on the property of computer programs known as “locality of reference”.
  • 25.
     Analysis ofprograms indicates that many instructions in localized areas of a program are executed repeatedly during some period of time, while the others are accessed relatively less frequently.  These instructions may be the ones in a loop, nested loop or few procedures calling each other repeatedly.  This is called “locality of reference”.  Temporal locality of reference:  Recently executed instruction is likely to be executed again very soon.  Spatial locality of reference:  Instructions with addresses close to a recently instruction are likely to be executed soon.
  • 26.
    • Processor issuesa Read request, a block of words is transferred from the main memory to the cache, one word at a time. • Subsequent references to the data in this block of words are found in the cache. • At any given time, only some blocks in the main memory are held in the cache. Which blocks in the main memory are in the cache is determined by a “mapping function”. • When the cache is full, and a block of words needs to be transferred from the main memory, some block of words in the cache must be replaced. This is determined by a “replacement algorithm”. Cache Main memory Processor
  • 27.
    • Existence ofa cache is transparent to the processor. The processor issues Read and Write requests in the same manner. • If the data is in the cache it is called a Read or Write hit. • Read hit:  The data is obtained from the cache. • Write hit:  Cache has a replica of the contents of the main memory.  Contents of the cache and the main memory may be updated simultaneously. This is the write-through protocol.  Update the contents of the cache, and mark it as updated by setting a bit known as the dirty bit or modified bit. The contents of the main memory are updated when this block is replaced. This is write-back or copy-back protocol.
  • 28.
    • If thedata is not present in the cache, then a Read miss or Write miss occurs. • Read miss:  Block of words containing this requested word is transferred from the memory.  After the block is transferred, the desired word is forwarded to the processor.  The desired word may also be forwarded to the processor as soon as it is transferred without waiting for the entire block to be transferred. This is called load-through or early-restart. • Write-miss:  Write-through protocol is used, then the contents of the main memory are updated directly.  If write-back protocol is used, the block containing the addressed word is first brought into the cache. The desired word is overwritten with new information.
  • 29.
    • A bitcalled as “valid bit” is provided for each block. • If the block contains valid data, then the bit is set to 1, else it is 0. • Valid bits are set to 0, when the power is just turned on. • When a block is loaded into the cache for the first time, the valid bit is set to 1. • Data transfers between main memory and disk occur directly bypassing the cache. • When the data on a disk changes, the main memory block is also updated. • However, if the data is also resident in the cache, then the valid bit is set to 0. • What happens if the data in the disk and main memory changes and the write-back protocol is being used? • In this case, the data in the cache may also have changed and is indicated by the dirty bit. • The copies of the data in the cache, and the main memory are different. This is called the cache coherence problem. • One option is to force a write-back before the main memory is updated from the disk.
  • 30.
     Mapping functionsdetermine how memory blocks are placed in the cache.  A simple processor example:  Cache consisting of 128 blocks of 16 words each.  Total size of cache is 2048 (2K) words.  Main memory is addressable by a 16-bit address.  Main memory has 64K words.  Main memory has 4K blocks of 16 words each.  Three mapping functions:  Direct mapping  Associative mapping  Set-associative mapping.
  • 31.
    Main memory Block 0 Block1 Block 127 Block 128 Block 129 Block 255 Block 256 Block 257 Block 4095 7 4 Main memory address Tag Block Word 5 tag tag tag Cache Block 0 Block 1 Block 127 •Block j of the main memory maps to j modulo 128 of the cache. 0 maps to 0, 129 maps to 1. •More than one memory block is mapped onto the same position in the cache. •May lead to contention for cache blocks even if the cache is not full. •Resolve the contention by allowing new block to replace the old block, leading to a trivial replacement algorithm. •Memory address is divided into three fields: - Low order 4 bits determine one of the 16 words in a block. - When a new block is brought into the cache, the the next 7 bits determine which cache block this new block is placed in. - High order 5 bits determine which of the possible 32 blocks is currently present in the cache. These are tag bits. •Simple to implement but not very flexible.
  • 32.
    •Main memory blockcan be placed into any cache position. •Memory address is divided into two fields: - Low order 4 bits identify the word within a block. - High order 12 bits or tag bits identify a memory block when it is resident in the cache. •Flexible, and uses cache space efficiently. •Replacement algorithms can be used to replace an existing block in the cache when the cache is full. •Cost is higher than direct-mapped cache because of the need to search all 128 patterns to determine whether a given block is in the cache. Main memory Block 0 Block 1 Block 127 Block 128 Block 129 Block 255 Block 256 Block 257 Block 4095 4 Main memory address Tag Word 12 tag tag tag Cache Block 0 Block 1 Block 127
  • 33.
    Blocks of cacheare grouped into sets. Mapping function allows a block of the main memory to reside in any block of a specific set. Divide the cache into 64 sets, with two blocks per set. Memory block 0, 64, 128 etc. map to block 0, and they can occupy either of the two positions. Memory address is divided into three fields: - 6 bit field determines the set number. - High order 6 bit fields are compared to the tag fields of the two blocks in a set. Set-associative mapping combination of direct and associative mapping. Number of blocks per set is a design parameter. - One extreme is to have all the blocks in one set, requiring no set bits (fully associative mapping). - Other extreme is to have one block per set, is the same as direct mapping. Main memory Block 0 Block 1 Block 63 Block 64 Block 65 Block 127 Block 128 Block 129 Block 4095 7 4 Main memory address Tag Block Word 5 tag tag tag Cache Block 1 Block 2 Block 126 Block 127 Block 3 Block 0 tag tag tag
  • 34.
  • 35.
     A keydesign objective of a computer system is to achieve the best possible performance at the lowest possible cost.  Price/performance ratio is a common measure of success.  Performance of a processor depends on:  How fast machine instructions can be brought into the processor for execution.  How fast the instructions can be executed.
  • 36.
     Divides thememory system into a number of memory modules. Each module has its own address buffer register (ABR) and data buffer register (DBR).  Arranges addressing so that successive words in the address space are placed in different modules.  When requests for memory access involve consecutive addresses, the access will be to different modules.  Since parallel access to these modules is possible, the average rate of fetching words from the Main Memory can be increased.
  • 37.
     Consecutive wordsare placed in a module.  High-order k bits of a memory address determine the module.  Low-order m bits of a memory address determine the word within a module.  When a block of words is transferred from main memory to cache, only one module is busy at a time. m bits Address in module MM address i k bits Module Module Module Module DBR ABR DBR ABR ABR DBR 0 n 1 - i k bits 0 Module Module Module Module MM address DBR ABR ABR DBR ABR DBR Address in module 2 k 1 - mbits •Consecutive words are located in consecutive modules. •Consecutive addresses can be located in consecutive modules. •While transferring a block of data, several memory modules can be kept busy at the same time.
  • 38.
     Hit rate Miss penalty  Hit rate can be improved by increasing block size, while keeping cache size constant  Block sizes that are neither very small nor very large give best results.  Miss penalty can be reduced if load-through approach is used when loading new blocks into cache.
  • 39.
     In highperformance processors 2 levels of caches are normally used.  Avg access time in a system with 2 levels of caches is T ave = h1c1+(1-h1)h2c2+(1-h1)(1-h2)M
  • 40.
    Write buffer  Write-through: •Each write operation involves writing to the main memory. • If the processor has to wait for the write operation to be complete, it slows down the processor. • Processor does not depend on the results of the write operation. • Write buffer can be included for temporary storage of write requests. • Processor places each write request into the buffer and continues execution. • If a subsequent Read request references data which is still in the write buffer, then this data is referenced in the write buffer.  Write-back: • Block is written back to the main memory when it is replaced. • If the processor waits for this write to complete, before reading the new block, it is slowed down. • Fast write buffer can hold the block to be written, and the new block can be read first.
  • 41.
    Prefetching • New dataare brought into the processor when they are first needed. • Processor has to wait before the data transfer is complete. • Prefetch the data into the cache before they are actually needed, or a before a Read miss occurs. • Prefetching can be accomplished through software by including a special instruction in the machine language of the processor.  Inclusion of prefetch instructions increases the length of the programs. • Prefetching can also be accomplished using hardware:  Circuitry that attempts to discover patterns in memory references and then prefetches according to this pattern.
  • 42.
    Lockup-Free Cache • Prefetchingscheme does not work if it stops other accesses to the cache until the prefetch is completed. • A cache of this type is said to be “locked” while it services a miss. • Cache structure which supports multiple outstanding misses is called a lockup free cache. • Since only one miss can be serviced at a time, a lockup free cache must include circuits that keep track of all the outstanding misses. • Special registers may hold the necessary information about these misses.
  • 43.
  • 44.
    44  Recall thatan important challenge in the design of a computer system is to provide a large, fast memory system at an affordable cost.  Architectural solutions to increase the effective speed and size of the memory system.  Cache memories were developed to increase the effective speed of the memory system.  Virtual memory is an architectural solution to increase the effective size of the memory system.
  • 45.
    45  Recall thatthe addressable memory space depends on the number of address bits in a computer.  For example, if a computer issues 32-bit addresses, the addressable memory space is 4G bytes.  Physical main memory in a computer is generally not as large as the entire possible addressable space.  Physical memory typically ranges from a few hundred megabytes to 1G bytes.  Large programs that cannot fit completely into the main memory have their parts stored on secondary storage devices such as magnetic disks.  Pieces of programs must be transferred to the main memory from secondary storage before they can be executed.
  • 46.
    46  When anew piece of a program is to be transferred to the main memory, and the main memory is full, then some other piece in the main memory must be replaced.  Recall this is very similar to what we studied in case of cache memories.  Operating system automatically transfers data between the main memory and secondary storage.  Application programmer need not be concerned with this transfer.  Also, application programmer does not need to be aware of the limitations imposed by the available physical memory.
  • 47.
    47  Techniques thatautomatically move program and data between main memory and secondary storage when they are required for execution are called virtual-memory techniques.  Programs and processors reference an instruction or data independent of the size of the main memory.  Processor issues binary addresses for instructions and data.  These binary addresses are called logical or virtual addresses.  Virtual addresses are translated into physical addresses by a combination of hardware and software subsystems.  If virtual address refers to a part of the program that is currently in the main memory, it is accessed immediately.  If the address refers to a part of the program that is not currently in the main memory, it is first transferred to the main memory before it can be used.
  • 48.
    48 Data Data DMA transfer Physical address Physicaladdress Virtual address Disk storage Main memory Cache MMU Processor •Memory management unit (MMU) translates virtual addresses into physical addresses. •If the desired data or instructions are in the main memory they are fetched as described previously. •If the desired data or instructions are not in the main memory, they must be transferred from secondary storage to the main memory. •MMU causes the operating system to bring the data from the secondary storage into the main memory.
  • 49.
    49  Assume thatprogram and data are composed of fixed-length units called pages.  A page consists of a block of words that occupy contiguous locations in the main memory.  Page is a basic unit of information that is transferred between secondary storage and main memory.  Size of a page commonly ranges from 2K to 16K bytes.  Pages should not be too small, because the access time of a secondary storage device is much larger than the main memory.  Pages should not be too large, else a large portion of the page may not be used, and it will occupy valuable space in the main memory.
  • 50.
    50  Concepts ofvirtual memory are similar to the concepts of cache memory.  Cache memory:  Introduced to bridge the speed gap between the processor and the main memory.  Implemented in hardware.  Virtual memory:  Introduced to bridge the speed gap between the main memory and secondary storage.  Implemented in part by software.
  • 51.
    51  Each virtualor logical address generated by a processor is interpreted as a virtual page number (high-order bits) plus an offset (low- order bits) that specifies the location of a particular byte within that page.  Information about the main memory location of each page is kept in the page table.  Main memory address where the page is stored.  Current status of the page.  Area of the main memory that can hold a page is called as page frame.  Starting address of the page table is kept in a page table base register.
  • 52.
    52  Virtual pagenumber generated by the processor is added to the contents of the page table base register.  This provides the address of the corresponding entry in the page table.  The contents of this location in the page table give the starting address of the page if the page is currently in the main memory.
  • 53.
    53 Page frame Virtual addressfrom processor in memory Offset Offset Virtual page number Page table address Page table base register Control bits Physical address in main memory PAGE TABLE Page frame + Virtual address is interpreted as page number and offset. Page table holds information about each page. This includes the starting address of the page in the main memory. PTBR holds the address of the page table. PTBR + virtual page number provide the entry of the page in the page table. This entry has the starting location of the page.
  • 54.
    54  Page tableentry for a page also includes some control bits which describe the status of the page while it is in the main memory.  One bit indicates the validity of the page.  Indicates whether the page is actually loaded into the main memory.  Allows the operating system to invalidate the page without actually removing it.  One bit indicates whether the page has been modified during its residency in the main memory.  This bit determines whether the page should be written back to the disk when it is removed from the main memory.  Similar to the dirty or modified bit in case of cache memory.
  • 55.
    55  Other controlbits for various other types of restrictions that may be imposed.  For example, a program may only have read permission for a page, but not write or modify permissions.
  • 56.
    56  Where shouldthe page table be located?  Recall that the page table is used by the MMU for every read and write access to the memory.  Ideal location for the page table is within the MMU.  Page table is quite large.  MMU is implemented as part of the processor chip.  Impossible to include a complete page table on the chip.  Page table is kept in the main memory.  A copy of a small portion of the page table can be accommodated within the MMU.  Portion consists of page table entries that correspond to the most recently accessed pages.
  • 57.
    57  A smallcache called as Translation Lookaside Buffer (TLB) is included in the MMU.  TLB holds page table entries of the most recently accessed pages.  Recall that cache memory holds most recently accessed blocks from the main memory.  Operation of the TLB and page table in the main memory is similar to the operation of the cache and main memory.  Page table entry for a page includes:  Address of the page frame where the page resides in the main memory.  Some control bits.  In addition to the above for each page, TLB must hold the virtual page number for each page.
  • 58.
    58 No Yes Hit Miss Virtual address fromprocessor TLB Offset Virtual page number number Virtual page Page frame in memory Control bits Offset Page frame =? Physical address in main memory Associative-mapped TLB High-order bits of the virtual address generated by the processor select the virtual page. These bits are compared to the virtual page numbers in the TLB. If there is a match, a hit occurs and the corresponding address of the page frame is read. If there is no match, a miss occurs and the page table within the main memory must be consulted. Set-associative mapped TLBs are found in commercial processors.
  • 59.
    59  How tokeep the entries of the TLB coherent with the contents of the page table in the main memory?  Operating system may change the contents of the page table in the main memory.  Simultaneously it must also invalidate the corresponding entries in the TLB.  A control bit is provided in the TLB to invalidate an entry.  If an entry is invalidated, then the TLB gets the information for that entry from the page table.  Follows the same process that it would follow if the entry is not found in the TLB or if a “miss” occurs.
  • 60.
    60  What happensif a program generates an access to a page that is not in the main memory?  In this case, a page fault is said to occur.  Whole page must be brought into the main memory from the disk, before the execution can proceed.  Upon detecting a page fault by the MMU, following actions occur:  MMU asks the operating system to intervene by raising an exception.  Processing of the active task which caused the page fault is interrupted.  Control is transferred to the operating system.  Operating system copies the requested page from secondary storage to the main memory.  Once the page is copied, control is returned to the task which was interrupted.
  • 61.
    61  Servicing ofa page fault requires transferring the requested page from secondary storage to the main memory.  This transfer may incur a long delay.  While the page is being transferred the operating system may:  Suspend the execution of the task that caused the page fault.  Begin execution of another task whose pages are in the main memory.  Enables efficient use of the processor.
  • 62.
    62  How toensure that the interrupted task can continue correctly when it resumes execution?  There are two possibilities:  Execution of the interrupted task must continue from the point where it was interrupted.  The instruction must be restarted.  Which specific option is followed depends on the design of the processor.
  • 63.
    63  When anew page is to be brought into the main memory from secondary storage, the main memory may be full.  Some page from the main memory must be replaced with this new page.  How to choose which page to replace?  This is similar to the replacement that occurs when the cache is full.  The principle of locality of reference (?) can also be applied here.  A replacement strategy similar to LRU can be applied.  Since the size of the main memory is relatively larger compared to cache, a relatively large amount of programs and data can be held in the main memory.  Minimizes the frequency of transfers between secondary storage and main memory.
  • 64.
    64  A pagemay be modified during its residency in the main memory.  When should the page be written back to the secondary storage?  Recall that we encountered a similar problem in the context of cache and main memory:  Write-through protocol(?)  Write-back protocol(?)  Write-through protocol cannot be used, since it will incur a long delay each time a small amount of data is written to the disk.
  • 65.
  • 66.
     Operating systemis concerned with transferring programs and data between secondary storage and main memory.  Operating system needs memory routines in addition to the other routines.  Operating system routines are assembled into a virtual address space called system space.  System space is separate from the space in which user application programs reside.  This is user space.  Virtual address space is divided into one system space + several user spaces.
  • 67.
     Recall thatthe Memory Management Unit (MMU) translates logical or virtual addresses into physical addresses.  MMU uses the contents of the page table base register to determine the address of the page table to be used in the translation.  Changing the contents of the page table base register can enable us to use a different page table, and switch from one space to another.  At any given time, the page table base register can point to one page table.  Thus, only one page table can be used in the translation process at a given time.  Pages belonging to only one space are accessible at any given time.
  • 68.
     When multiple,independent user programs coexist in the main memory, how to ensure that one program does not modify/destroy the contents of the other?  Processor usually has two states of operation:  Supervisor state.  User state.  Supervisor state:  Operating system routines are executed.  User state:  User programs are executed.  Certain privileged instructions cannot be executed in user state.  These privileged instructions include the ones which change page table base register.  Prevents one user from accessing the space of other users.
  • 69.
  • 70.
  • 71.
    Sector 0, track0 Sector 3, track n Figure 5.30. Organization of one surface of a disk. Sector 0, track 1
  • 72.
     Sector header Following the data, there is an error- correction code (ECC).  Formatting process  Access time – seek time / rotational delay (latency time)  Data buffer/cache
  • 73.
    Processor Main memory Systembus Figure 5.31. Disks connected to the system bus. Disk controller Disk drive Disk drive
  • 74.
     Seek  Read Write  Error checking
  • 75.
     Redundant Arrayof Inexpensive Disks  Using multiple disks makes it cheaper for huge storage, and also possible to improve the reliability of the overall system.  RAID0 – data striping  RAID1 – identical copies of data on two disks  RAID2, 3, 4 – increased reliability  RAID5 – parity-based error-recovery
  • 76.
    (a) Cross-section Source DetectorSource Detector Source Detector No reflection Reflection Reflection Pit Land 0 0 0 1 0 0 0 0 1 0 0 0 1 0 0 1 0 0 1 0 (c) Stored binary pattern Figure 5.32. Optical disk. 1 (b) Transition from pit to land
  • 77.
     CD-ROM  CD-Recordable(CD-R)  CD-ReWritable (CD-RW)  DVD  DVD-RAM
  • 78.
    Figure 5.33. Organizationof data on magnetic tape. File File mark mark File 7 or 9 gap gap File gap Record Record Record Record bits • • • • • • • •