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    Replace substring in list of strings - Python

    Last Updated : 11 Jul, 2025
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    We are given a list of strings, and our task is to replace a specific substring within each string with a new substring. This is useful when modifying text data in bulk. For example, given a = ["hello world", "world of code", "worldwide"], replacing "world" with "universe" should result in ["hello universe", "universe of code", "universewide"]. Let's discuss different methods to do this in Python.

    Using List Comprehension with replace()

    replace() method replaces occurrences of a substring in a string. Using list comprehension, we can apply it to every string in the list efficiently.

    Python
    a = ["hello world", "world of code", "worldwide"]  
    old_substring = "world"  
    new_substring = "universe"  
    
    res = [s.replace(old_substring, new_substring) for s in a]  
    print(res) 
    

    Output
    ['hello universe', 'universe of code', 'universewide']
    

    Explanation:

    • The replace() function replaces all occurrences of "world" with "universe" in each string.
    • List comprehension iterates through the list and applies replace() to every string.

    Using map()

    map() function applies replace() to each string in the list without using explicit loops.

    Python
    a = ["hello world", "world of code", "worldwide"]  
    s1 = "world"  
    s2 = "universe"  
    
    res = list(map(lambda s: s.replace(s1, s2), a))  
    print(res)
    

    Output
    ['hello universe', 'universe of code', 'universewide']
    

    Explanation:

    • map() applies the replace() function to each string in a.
    • The lambda function takes each string and replaces "world" with "universe".
    • list(map(...)) ensures that the result is stored as a list.

    Using for Loop and replace()

    A for loop allows modifying the list step by step, storing results in a new list.

    Python
    a = ["hello world", "world of code", "worldwide"]  
    s1 = "world"  
    s2 = "universe"  
    
    res = []  
    for s in a:  
        s3 = s.replace(s1, s2) 
        res.append(s3)  
    
    print(res)
    

    Output
    ['hello universe', 'universe of code', 'universewide']
    

    Explanation:

    • The for loop iterates over each string in a.
    • s.replace(s1, s2) replaces "world" with "universe" in each string.
    • The modified string is stored in result using append().

    Using re.sub() for Pattern-Based Replacement

    re.sub() function allows replacing substrings based on patterns.

    Python
    import re  
    
    a = ["hello world", "world of code", "worldwide"]  
    s1 = "world"  
    s2 = "universe"  
    
    res = [re.sub(s1, s2, s) for s in a]  
    print(res)  
    

    Output
    ['hello universe', 'universe of code', 'universewide']
    

    Explanation:

    • re.sub(pattern, replacement, string) replaces "world" with "universe" in each string.
    • This method is useful when replacing text based on complex patterns rather than exact substrings.

    Using str.translate()

    If replacing single characters instead of substrings, str.translate() is a faster alternative.

    Python
    a = ["hello world", "world of code", "worldwide"]  
    
    trans_table = str.maketrans("o", "0")  
    
    res = [s.translate(trans_table) for s in a]  
    print(res) 
    

    Output
    ['hell0 w0rld', 'w0rld 0f c0de', 'w0rldwide']
    

    Explanation:

    • str.maketrans("o", "0") creates a mapping to replace "o" with "0".
    • s.translate(trans_table) applies this mapping to each string in a.
    • This method is limited to character replacements rather than full substrings.

    Related Articles:

    • Python Lists
    • Python String
    • List Comprehension in Python
    • Python String replace() Method
    • Python map() function
    • Python For Loops
    • re.sub() - Python RegEx
    • Python String translate() Method
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    Article Tags :
    • Python
    • Python Programs
    • Python list-programs

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