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    Check if a given string is binary string or not - Python

    Last Updated : 01 Nov, 2025
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    A binary string is a string that contains only the characters '0' and '1'. For example, "101010" is a binary string, while "10201" is not. Our task is to check if a given string is a binary string or not.

    Using all()

    all() function in Python is a built-in method that returns True if all elements of an iterable satisfy a given condition, and False otherwise.

    Python
    s = "101010000111"
    if all(c in '01' for c in s):
        print("Yes")
    else:
        print("No")
    

    Output
    Yes
    

    Explanation:

    • all(c in '01' for c in s): creates a generator that iterates through each character in s.
    • Checks if each character belongs to the set {'0','1'}.
    • Short-circuit evaluation: all() stops immediately if a character fails the condition, making it fast for large strings.

    Using set()

    set() can be used to quickly identify the unique characters in a string.

    Python
    s = "101010000111"
    if set(s).issubset({'0', '1'}):
        print("Yes")
    else:
        print("No")
    

    Output
    Yes
    

    Explanation:

    • set(s): converts the string into a set of unique characters.
    • issubset({'0', '1'}): checks if all unique characters are either '0' or '1'.
    • Efficient for strings with repeated characters as it reduces unnecessary checks.

    Using Regular Expressions

    Regular expressions (regex) provide a powerful and flexible way to match patterns in strings.

    Python
    import re
    s = "101010000111"
    if re.fullmatch('[01]+', s):
        print("Yes")
    else:
        print("No")
    

    Output
    Yes
    

    Explanation:

    • [01]+ matches one or more occurrences of '0' or '1'.
    • re.fullmatch(): ensures the entire string matches the pattern.
    • Regex is powerful and concise but slightly slower than all() or set-based checks for simple patterns.

    Using a for Loop

    A simple for loop can iterate through each character of the string and manually check whether it is '0' or '1'.

    Python
    s = "101010000111"
    for char in s:
        if char not in '01':
            print("No")
            break
    else:
        print("Yes")
    

    Output
    Yes
    

    Explanation:

    • Iterates through each character, checking membership in '01'.
    • Stops immediately when an invalid character is found using break.
    • Simple to understand, but concatenation or repeated membership checks are slower than generator-based all().

    Related Articles:

    • Check for Binary String
    • Check if two binary strings can be made equal by swapping 1s occurring before 0s
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