Prepared by Mahmoud Eltaweel
Attributes Control Charts
Control Charts
Variables
Moving Range
N=1
Xbar R
2≤ 𝒏 ≤ 𝟗
Xbar S
N≥ 𝟗
Attributes
Non-confirming
(defective)
Variable sample size
(fraction
nonconforming)
Variable
approximate
standardized
Constant sample
size
(Number
nonconforming)
Non-comformities
(Defects)
C chart
Non-confirming
(variable sample size)
𝑷𝒊 =
𝑫𝒊
𝒏𝒊
Variable
UCL= (𝑷 + 𝟑
"𝑷 𝟏%"𝑷
𝒏 𝒊
CL=(𝑷
𝑳𝑪𝑳 = (𝑷 − 𝟑
"𝑷 𝟏%"𝑷
𝒏 𝒊
or
zero if value is negative
sign
Non-confirming
(variable sample
size)
𝑷𝒊 =
𝑫𝒊
𝒏𝒊
Standardized
UCL= 𝟑
CL=0
𝑳𝑪𝑳 = −𝟑
𝒁𝒊 =
𝑷𝒊 − (𝑷
(𝑷 𝟏 − (𝑷
𝒏𝒊
Non-confirming
(variable sample size)
𝑷𝒊 =
𝑫𝒊
𝒏𝒊
Approximate
UCL= (𝑷 + 𝟑
"𝑷 𝟏%"𝑷
"𝒏
CL=(𝑷
𝑳𝑪𝑳 = (𝑷 + 𝟑
"𝑷 𝟏%"𝑷
"𝒏
or zero if value is
negative sign
Non-confirming
(Constant sample size)
UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷
CL= 𝒏(𝑷
𝑳𝑪𝑳 = 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷
or zero if value is negative
sign
Question 1
• The data in following table
represent the results of
inspecting all units of a
personal computer produced
for the past ten days. Does
the process appear to be in
control?
Question 2
A maintenance group improves the
effectiveness of its repair work by
monitoring the number of
maintenance requests that require a
second call to complete the repair.
Twenty weeks of data are shown in
the following table.
1. Using an average sample size,
find trial control limits for this
process, and design a control
chart for controlling future
production.
2. Construct a standardized control
chart for the data
0𝑃 =
∑𝐷𝑖
∑𝑛'
=
83
3750
0𝑛 = 187.5
UCL= (𝑷 + 𝟑
"𝑷 𝟏%"𝑷
"𝒏
CL=(𝑷
𝑳𝑪𝑳 = (𝑷 + 𝟑
"𝑷 𝟏%"𝑷
"𝒏
or zero if value is
negative sign
Question 3
A process is controlled with a fraction
nonconforming control chart with three-
sigma limits, n = 100, UCL = 0.161, center
line = 0.080, and LCL = 0.
Find the equivalent control chart for the
number nonconforming.
Use the correct approximation to find the
probability of a type II error if the process
fraction nonconforming shifts to 0.2.
Find the equivalent control chart for the number nonconforming
Non-confirming
(Constant sample size)
UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷
CL= 𝒏(𝑷
𝑳𝑪𝑳 = 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷
or zero if value is negative
sign
n=100
Fraction nonconforming
CL=(𝑷 = 𝟎. 𝟎𝟖
UCL= 0.161
LCL=0
Number nonconforming
CL= 𝒏(𝑷 = 100(0.08)=8
UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷 = 8+𝟑 𝟖 𝟏 − 𝟎. 𝟎𝟖 =16.14
LCL= 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷 = 8−𝟑 𝟖 𝟏 − 𝟎. 𝟎𝟖 =-0.138 =0
Use the correct approximation to find the probability of a type II error if the process
fraction nonconforming shifts to 0.2.
Type II error or (𝛽) is when you accept the rejected
Type I error or (𝛼) 𝑖𝑠 𝑤ℎ𝑒𝑛 𝑦𝑜𝑢 𝑟𝑒𝑗𝑒𝑐𝑡 𝑎𝑐𝑐𝑒𝑝𝑡𝑒𝑑
𝑛𝑝()* = 100 0.2 = 20

variable non-confirming Q&A

  • 1.
    Prepared by MahmoudEltaweel Attributes Control Charts
  • 2.
    Control Charts Variables Moving Range N=1 XbarR 2≤ 𝒏 ≤ 𝟗 Xbar S N≥ 𝟗 Attributes Non-confirming (defective) Variable sample size (fraction nonconforming) Variable approximate standardized Constant sample size (Number nonconforming) Non-comformities (Defects) C chart
  • 3.
    Non-confirming (variable sample size) 𝑷𝒊= 𝑫𝒊 𝒏𝒊 Variable UCL= (𝑷 + 𝟑 "𝑷 𝟏%"𝑷 𝒏 𝒊 CL=(𝑷 𝑳𝑪𝑳 = (𝑷 − 𝟑 "𝑷 𝟏%"𝑷 𝒏 𝒊 or zero if value is negative sign Non-confirming (variable sample size) 𝑷𝒊 = 𝑫𝒊 𝒏𝒊 Standardized UCL= 𝟑 CL=0 𝑳𝑪𝑳 = −𝟑 𝒁𝒊 = 𝑷𝒊 − (𝑷 (𝑷 𝟏 − (𝑷 𝒏𝒊 Non-confirming (variable sample size) 𝑷𝒊 = 𝑫𝒊 𝒏𝒊 Approximate UCL= (𝑷 + 𝟑 "𝑷 𝟏%"𝑷 "𝒏 CL=(𝑷 𝑳𝑪𝑳 = (𝑷 + 𝟑 "𝑷 𝟏%"𝑷 "𝒏 or zero if value is negative sign Non-confirming (Constant sample size) UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷 CL= 𝒏(𝑷 𝑳𝑪𝑳 = 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷 or zero if value is negative sign
  • 4.
    Question 1 • Thedata in following table represent the results of inspecting all units of a personal computer produced for the past ten days. Does the process appear to be in control?
  • 6.
    Question 2 A maintenancegroup improves the effectiveness of its repair work by monitoring the number of maintenance requests that require a second call to complete the repair. Twenty weeks of data are shown in the following table. 1. Using an average sample size, find trial control limits for this process, and design a control chart for controlling future production. 2. Construct a standardized control chart for the data
  • 7.
    0𝑃 = ∑𝐷𝑖 ∑𝑛' = 83 3750 0𝑛 =187.5 UCL= (𝑷 + 𝟑 "𝑷 𝟏%"𝑷 "𝒏 CL=(𝑷 𝑳𝑪𝑳 = (𝑷 + 𝟑 "𝑷 𝟏%"𝑷 "𝒏 or zero if value is negative sign
  • 9.
    Question 3 A processis controlled with a fraction nonconforming control chart with three- sigma limits, n = 100, UCL = 0.161, center line = 0.080, and LCL = 0. Find the equivalent control chart for the number nonconforming. Use the correct approximation to find the probability of a type II error if the process fraction nonconforming shifts to 0.2.
  • 10.
    Find the equivalentcontrol chart for the number nonconforming Non-confirming (Constant sample size) UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷 CL= 𝒏(𝑷 𝑳𝑪𝑳 = 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷 or zero if value is negative sign n=100 Fraction nonconforming CL=(𝑷 = 𝟎. 𝟎𝟖 UCL= 0.161 LCL=0 Number nonconforming CL= 𝒏(𝑷 = 100(0.08)=8 UCL= 𝒏(𝑷 + 𝟑 𝒏(𝑷 𝟏 − (𝑷 = 8+𝟑 𝟖 𝟏 − 𝟎. 𝟎𝟖 =16.14 LCL= 𝒏(𝑷 − 𝟑 𝒏(𝑷 𝟏 − (𝑷 = 8−𝟑 𝟖 𝟏 − 𝟎. 𝟎𝟖 =-0.138 =0
  • 11.
    Use the correctapproximation to find the probability of a type II error if the process fraction nonconforming shifts to 0.2. Type II error or (𝛽) is when you accept the rejected Type I error or (𝛼) 𝑖𝑠 𝑤ℎ𝑒𝑛 𝑦𝑜𝑢 𝑟𝑒𝑗𝑒𝑐𝑡 𝑎𝑐𝑐𝑒𝑝𝑡𝑒𝑑 𝑛𝑝()* = 100 0.2 = 20