Cryptography and Network
Security
Third Edition
by William Stallings
Lecture slides by Lawrie Brown
Chapter 9 – Public Key
Cryptography and RSA
Every Egyptian received two names, which were
known respectively as the true name and the
good name, or the great name and the little
name; and while the good or little name was
made public, the true or great name appears to
have been carefully concealed.
—The Golden Bough, Sir James George Frazer
Private-Key Cryptography
• traditional private/secret/single key
cryptography uses one key
• shared by both sender and receiver
• if this key is disclosed communications are
compromised
• also is symmetric, parties are equal
• hence does not protect sender from
receiver forging a message & claiming is
sent by sender
Public-Key Cryptography
• probably most significant advance in the
3000 year history of cryptography
• uses two keys – a public & a private key
• asymmetric since parties are not equal
• uses clever application of number
theoretic concepts to function
• complements rather than replaces private
key crypto
Public-Key Cryptography
• public-key/two-key/asymmetric cryptography
involves the use of two keys:
– a public-key, which may be known by anybody, and
can be used to encrypt messages, and verify
signatures
– a private-key, known only to the recipient, used to
decrypt messages, and sign (create) signatures
• is asymmetric because
– those who encrypt messages or verify signatures
cannot decrypt messages or create signatures
Public-Key Cryptography
Why Public-Key Cryptography?
• developed to address two key issues:
– key distribution – how to have secure
communications in general without having to
trust a KDC with your key
– digital signatures – how to verify a message
comes intact from the claimed sender
• public invention due to Whitfield Diffie &
Martin Hellman at Stanford Uni in 1976
– known earlier in classified community
Public-Key Characteristics
• Public-Key algorithms rely on two keys
with the characteristics that it is:
– computationally infeasible to find decryption
key knowing only algorithm & encryption key
– computationally easy to en/decrypt messages
when the relevant (en/decrypt) key is known
– either of the two related keys can be used for
encryption, with the other used for decryption
(in some schemes)
Public-Key Cryptosystems
Public-Key Applications
• can classify uses into 3 categories:
– encryption/decryption (provide secrecy)
– digital signatures (provide authentication)
– key exchange (of session keys)
• some algorithms are suitable for all uses,
others are specific to one
Security of Public Key Schemes
• like private key schemes brute force exhaustive
search attack is always theoretically possible
• but keys used are too large (>512bits)
• security relies on a large enough difference in
difficulty between easy (en/decrypt) and hard
(cryptanalyse) problems
• more generally the hard problem is known, its
just made too hard to do in practise
• requires the use of very large numbers
• hence is slow compared to private key schemes
RSA
• by Rivest, Shamir & Adleman of MIT in 1977
• best known & widely used public-key scheme
• based on exponentiation in a finite (Galois) field
over integers modulo a prime
– nb. exponentiation takes O((log n)3) operations (easy)
• uses large integers (eg. 1024 bits)
• security due to cost of factoring large numbers
– nb. factorization takes O(e log n log log n) operations
(hard)
RSA Key Setup
• each user generates a public/private key pair by:
• selecting two large primes at random - p, q
• computing their system modulus N=p.q
– note ø(N)=(p-1)(q-1)
• selecting at random the encryption key e
• where 1<e<ø(N), gcd(e,ø(N))=1
• solve following equation to find decryption key d
– e.d=1 mod ø(N) and 0≤d≤N
• publish their public encryption key: KU={e,N}
• keep secret private decryption key: KR={d,p,q}
RSA Use
• to encrypt a message M the sender:
– obtains public key of recipient KU={e,N}
– computes: C=Me mod N, where 0≤M<N
• to decrypt the ciphertext C the owner:
– uses their private key KR={d,p,q}
– computes: M=Cd mod N
• note that the message M must be smaller
than the modulus N (block if needed)
Why RSA Works
• because of Euler's Theorem:
• aø(n)mod N = 1
– where gcd(a,N)=1
• in RSA have:
– N=p.q
– ø(N)=(p-1)(q-1)
– carefully chosen e & d to be inverses mod ø(N)
– hence e.d=1+k.ø(N) for some k
• hence :
Cd = (Me)d = M1+k.ø(N) = M1.(Mø(N))q =
M1.(1)q = M1 = M mod N
RSA Example
1. Select primes: p=17 & q=11
2. Compute n = pq =17×11=187
3. Compute ø(n)=(p–1)(q-1)=16×10=160
4. Select e : gcd(e,160)=1; choose e=7
5. Determine d: de=1 mod 160 and d < 160
Value is d=23 since 23×7=161= 10×160+1
6. Publish public key KU={7,187}
7. Keep secret private key KR={23,17,11}
RSA Example cont
• sample RSA encryption/decryption is:
• given message M = 88 (nb. 88<187)
• encryption:
C = 887 mod 187 = 11
• decryption:
M = 1123 mod 187 = 88
Exponentiation
• can use the Square and Multiply Algorithm
• a fast, efficient algorithm for exponentiation
• concept is based on repeatedly squaring base
• and multiplying in the ones that are needed to
compute the result
• look at binary representation of exponent
• only takes O(log2 n) multiples for number n
– eg. 75 = 74.71 = 3.7 = 10 mod 11
– eg. 3129 = 3128.31 = 5.3 = 4 mod 11
Exponentiation
RSA Key Generation
• users of RSA must:
– determine two primes at random - p, q
– select either e or d and compute the other
• primes p,q must not be easily derived
from modulus N=p.q
– means must be sufficiently large
– typically guess and use probabilistic test
• exponents e, d are inverses, so use
Inverse algorithm to compute the other
RSA Security
• three approaches to attacking RSA:
– brute force key search (infeasible given size
of numbers)
– mathematical attacks (based on difficulty of
computing ø(N), by factoring modulus N)
– timing attacks (on running of decryption)
Factoring Problem
• mathematical approach takes 3 forms:
– factor N=p.q, hence find ø(N) and then d
– determine ø(N) directly and find d
– find d directly
• currently believe all equivalent to factoring
– have seen slow improvements over the years
• as of Aug-99 best is 130 decimal digits (512) bit with GNFS
– biggest improvement comes from improved algorithm
• cf “Quadratic Sieve” to “Generalized Number Field Sieve”
– barring dramatic breakthrough 1024+ bit RSA secure
• ensure p, q of similar size and matching other constraints
Timing Attacks
• developed in mid-1990’s
• exploit timing variations in operations
– eg. multiplying by small vs large number
– or IF's varying which instructions executed
• infer operand size based on time taken
• RSA exploits time taken in exponentiation
• countermeasures
– use constant exponentiation time
– add random delays
– blind values used in calculations
Summary
• have considered:
– principles of public-key cryptography
– RSA algorithm, implementation, security

Public key cryptography and RSA algorithm

  • 1.
    Cryptography and Network Security ThirdEdition by William Stallings Lecture slides by Lawrie Brown
  • 2.
    Chapter 9 –Public Key Cryptography and RSA Every Egyptian received two names, which were known respectively as the true name and the good name, or the great name and the little name; and while the good or little name was made public, the true or great name appears to have been carefully concealed. —The Golden Bough, Sir James George Frazer
  • 3.
    Private-Key Cryptography • traditionalprivate/secret/single key cryptography uses one key • shared by both sender and receiver • if this key is disclosed communications are compromised • also is symmetric, parties are equal • hence does not protect sender from receiver forging a message & claiming is sent by sender
  • 4.
    Public-Key Cryptography • probablymost significant advance in the 3000 year history of cryptography • uses two keys – a public & a private key • asymmetric since parties are not equal • uses clever application of number theoretic concepts to function • complements rather than replaces private key crypto
  • 5.
    Public-Key Cryptography • public-key/two-key/asymmetriccryptography involves the use of two keys: – a public-key, which may be known by anybody, and can be used to encrypt messages, and verify signatures – a private-key, known only to the recipient, used to decrypt messages, and sign (create) signatures • is asymmetric because – those who encrypt messages or verify signatures cannot decrypt messages or create signatures
  • 6.
  • 7.
    Why Public-Key Cryptography? •developed to address two key issues: – key distribution – how to have secure communications in general without having to trust a KDC with your key – digital signatures – how to verify a message comes intact from the claimed sender • public invention due to Whitfield Diffie & Martin Hellman at Stanford Uni in 1976 – known earlier in classified community
  • 8.
    Public-Key Characteristics • Public-Keyalgorithms rely on two keys with the characteristics that it is: – computationally infeasible to find decryption key knowing only algorithm & encryption key – computationally easy to en/decrypt messages when the relevant (en/decrypt) key is known – either of the two related keys can be used for encryption, with the other used for decryption (in some schemes)
  • 9.
  • 10.
    Public-Key Applications • canclassify uses into 3 categories: – encryption/decryption (provide secrecy) – digital signatures (provide authentication) – key exchange (of session keys) • some algorithms are suitable for all uses, others are specific to one
  • 11.
    Security of PublicKey Schemes • like private key schemes brute force exhaustive search attack is always theoretically possible • but keys used are too large (>512bits) • security relies on a large enough difference in difficulty between easy (en/decrypt) and hard (cryptanalyse) problems • more generally the hard problem is known, its just made too hard to do in practise • requires the use of very large numbers • hence is slow compared to private key schemes
  • 12.
    RSA • by Rivest,Shamir & Adleman of MIT in 1977 • best known & widely used public-key scheme • based on exponentiation in a finite (Galois) field over integers modulo a prime – nb. exponentiation takes O((log n)3) operations (easy) • uses large integers (eg. 1024 bits) • security due to cost of factoring large numbers – nb. factorization takes O(e log n log log n) operations (hard)
  • 13.
    RSA Key Setup •each user generates a public/private key pair by: • selecting two large primes at random - p, q • computing their system modulus N=p.q – note ø(N)=(p-1)(q-1) • selecting at random the encryption key e • where 1<e<ø(N), gcd(e,ø(N))=1 • solve following equation to find decryption key d – e.d=1 mod ø(N) and 0≤d≤N • publish their public encryption key: KU={e,N} • keep secret private decryption key: KR={d,p,q}
  • 14.
    RSA Use • toencrypt a message M the sender: – obtains public key of recipient KU={e,N} – computes: C=Me mod N, where 0≤M<N • to decrypt the ciphertext C the owner: – uses their private key KR={d,p,q} – computes: M=Cd mod N • note that the message M must be smaller than the modulus N (block if needed)
  • 15.
    Why RSA Works •because of Euler's Theorem: • aø(n)mod N = 1 – where gcd(a,N)=1 • in RSA have: – N=p.q – ø(N)=(p-1)(q-1) – carefully chosen e & d to be inverses mod ø(N) – hence e.d=1+k.ø(N) for some k • hence : Cd = (Me)d = M1+k.ø(N) = M1.(Mø(N))q = M1.(1)q = M1 = M mod N
  • 16.
    RSA Example 1. Selectprimes: p=17 & q=11 2. Compute n = pq =17×11=187 3. Compute ø(n)=(p–1)(q-1)=16×10=160 4. Select e : gcd(e,160)=1; choose e=7 5. Determine d: de=1 mod 160 and d < 160 Value is d=23 since 23×7=161= 10×160+1 6. Publish public key KU={7,187} 7. Keep secret private key KR={23,17,11}
  • 17.
    RSA Example cont •sample RSA encryption/decryption is: • given message M = 88 (nb. 88<187) • encryption: C = 887 mod 187 = 11 • decryption: M = 1123 mod 187 = 88
  • 18.
    Exponentiation • can usethe Square and Multiply Algorithm • a fast, efficient algorithm for exponentiation • concept is based on repeatedly squaring base • and multiplying in the ones that are needed to compute the result • look at binary representation of exponent • only takes O(log2 n) multiples for number n – eg. 75 = 74.71 = 3.7 = 10 mod 11 – eg. 3129 = 3128.31 = 5.3 = 4 mod 11
  • 19.
  • 20.
    RSA Key Generation •users of RSA must: – determine two primes at random - p, q – select either e or d and compute the other • primes p,q must not be easily derived from modulus N=p.q – means must be sufficiently large – typically guess and use probabilistic test • exponents e, d are inverses, so use Inverse algorithm to compute the other
  • 21.
    RSA Security • threeapproaches to attacking RSA: – brute force key search (infeasible given size of numbers) – mathematical attacks (based on difficulty of computing ø(N), by factoring modulus N) – timing attacks (on running of decryption)
  • 22.
    Factoring Problem • mathematicalapproach takes 3 forms: – factor N=p.q, hence find ø(N) and then d – determine ø(N) directly and find d – find d directly • currently believe all equivalent to factoring – have seen slow improvements over the years • as of Aug-99 best is 130 decimal digits (512) bit with GNFS – biggest improvement comes from improved algorithm • cf “Quadratic Sieve” to “Generalized Number Field Sieve” – barring dramatic breakthrough 1024+ bit RSA secure • ensure p, q of similar size and matching other constraints
  • 23.
    Timing Attacks • developedin mid-1990’s • exploit timing variations in operations – eg. multiplying by small vs large number – or IF's varying which instructions executed • infer operand size based on time taken • RSA exploits time taken in exponentiation • countermeasures – use constant exponentiation time – add random delays – blind values used in calculations
  • 24.
    Summary • have considered: –principles of public-key cryptography – RSA algorithm, implementation, security