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 and [g ◦ f ](x), if they both equal x, they are inverses!](https://image.slidesharecdn.com/inversefunctionsandrelations-100630134313-phpapp01/75/Inverse-functions-and-relations-13-2048.jpg)
 = x + 6 – 6 = x [g ◦ f ](x) = x – 8 + 8 = x So, they ARE inverses of each other!](https://image.slidesharecdn.com/inversefunctionsandrelations-100630134313-phpapp01/75/Inverse-functions-and-relations-14-2048.jpg)
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Inverse functions and relations
1) An inverse function f^-1 interchanges the x and y values of the original function f. 2) For a function to have an inverse, it must be one-to-one, meaning each x maps to a single y and vice versa. 3) To find the inverse of a function algebraically, interchange x and y and solve for y. The graph of an inverse is the reflection of the original graph across the line y=x.
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Inverse functions and relations
- 1. Inverse Functions andRelations
- 2. Inverse Functions and Relations
- 3. Given any function,f, the inverse of the function, f -1 , is a relation that is formed by interchanging each (x,y) of f to a (y,x) of f -1 . Introduction
- 4. Let f bedefined as the set of values given by Let f -1 be defined as the set of values given by 10 -5 4 0 y-values 7 4 0 -2 x-values 7 4 0 -2 y-values 10 -5 4 0 x-values
- 5. For a functionto have an inverse that is a function, then the original function must be a 1:1 function. A 1:1 function is defined as a function in which each x is paired with exactly one y and y is paired with exactly one x. To be a function we can have no domain value paired with two range values .
- 6. That is, thefunction could not have (-3,5) and (-3,-3) as two points . To be a function the graph of the function must pass the “vertical line” test. To be a 1:1 function the graph of the function must also pass a “horizontal line” test.
- 7.
- 8. To find theinverse of a function: Replace f(x) with y. 2. Interchange x and y. 3. Solve for y. 4. Replace y with f -1 (x).
- 9. Example: Inverse RelationAlgebraically Example1 : Find the inverse relation algebraically for the function f ( x ) = 3 x + 2. y = 3 x + 2 Original equation defining f x = 3 y + 2 Switch x and y . 3 y + 2 = x Reverse sides of the equation. To calculate a value for the inverse of f , subtract 2, then divide by 3 . To find the inverse of a relation algebraically , interchange x and y and solve for y . y -1 = Solve for y.
- 10. y = x The graphs of a relation and its inverse are reflections in the line y = x . The ordered pairs of f a re given by the equation . Example 1a : Find the graph of the inverse relation geometrically from the graph of f ( x ) = x y 2 -2 -2 2 The ordered pairs of the inverse are given by .
- 11. Example2: Let f(x)= y = 3x , find the inverse. This is, f -1 : x = 3y . 5x - 1 5y - 1 Solve for y: x (5y – 1) = 3y. 5xy - x = 3y 5xy – 3y = x y(5x – 3) = x y = x 5x - 3
- 12. Example 3: Find the inverse of f(x) = f -1 (x) = -2x +2 (-2) (-2) Replace f(x) with y. Interchange x and y. Solve for y. Replace y with f-1(x).
- 13. Example 4: Twofunctions f and g are inverse functions if and only if both of their compositions are the identity function; f(x) = x. Determine whether and are inverse functions. You must do [f ◦ g](x) and [g ◦ f ](x), if they both equal x, they are inverses!
- 14. [f ◦ g](x)= x + 6 – 6 = x [g ◦ f ](x) = x – 8 + 8 = x So, they ARE inverses of each other!
- 15. Example: Composition ofFunctions It follows that g = f -1 . Example 5 :Verify that the function g ( x ) = is the inverse of f ( x ) = 2 x – 1. f( g ( x ) ) = 2 g ( x ) – 1 = 2( ) – 1 = ( x + 1) – 1 = x g ( f ( x ) ) = = = = x