Discrete Structures (CS 335)
Lecture 2

Mohsin Raza
University Institute of Information
Technology PMAS Arid Agriculture University
Rawalpindi
Compound Propositions
Producing new propositions from existing propositions.

Logical Operators or Connectives
1. Not



2. And

˄

3. Or

˅

4. Exclusive or



5. Implication



6. Biconditional


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Compound Propositions
Negation of a proposition
Let p be a proposition. The negation of p, denoted by
 p (also denoted by ~p), is the statement

“It is not the case that p”.
The proposition  p is read as “not p”. The truth
values of the negation of p,  p, is the opposite of the
truth value of p.

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Examples
1. Find the negation of the following proposition

p : Today is Friday.
The negation is
 p : It is not the case that today is Friday.

This negation can be more simply expressed by
 p : Today is not Friday.

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Examples
2. Write the negation of

“6 is negative”.
The negation is

“It is not the case that 6 is negative”.
or

“6 is nonnegative”.

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Truth Table (NOT)
• Unary Operator, Symbol: 
p

p

true

false

false

true

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Conjunction (AND)
Definition
Let p and q be propositions. The conjunction
of p and q, denoted by p˄q, is the proposition
“p and q”.
The conjunction p˄q is true when p and q are
both true and is false otherwise.

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Examples
1. Find the conjunction of the propositions p and q, where

p : Today is Friday.
q : It is raining today.
The conjunction is

p˄q : Today is Friday and it is raining today.

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Truth Table (AND)
• Binary Operator, Symbol: 
p

q

pq

true

true

true

true

false

false

false

true

false

false

false

false

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Disjunction (OR)
Definition

Let p and q be propositions. The disjunction
of p and q, denoted by p˅q, is the proposition
“p or q”.
The disjunction p˅q is false when both p and
q are false and is true otherwise.

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Examples
1. Find the disjunction of the propositions p and q,
where

p : Today is Friday.
q : It is raining today.
The disjunction is

p˅q : Today is Friday or it is raining today.

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Truth Table (OR)

• Binary Operator, Symbol: 
p

q

pq

true

true

true

true

false

true

false

true

true

false

false

false

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Exclusive OR (XOR)
Definition

Let p and q be propositions. The exclusive or
of p and q, denoted by pq, is the proposition
“pq”.
The exclusive or, p  q, is true when exactly
one of p and q is true and is false otherwise.

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Examples
1. Find the exclusive or of the propositions p and q,
where

p : Atif will pass the course CSC102.
q : Atif will fail the course CSC102.
The exclusive or is

pq : Atif will pass or fail the course CSC102.

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Truth Table (XOR)

• Binary Operator, Symbol: 
p

q

pq

true

true

false

true

false

true

false

true

true

false

false

false

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Examples (OR vs XOR)
The following proposition uses the (English) connective
“or”. Determine from the context whether “or” is intended
to be used in the inclusive or exclusive sense.

1. “Nabeel has one or two brothers”.
A person cannot have both one and two brothers.
Therefore, “or” is used in the exclusive sense.

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Examples (OR vs XOR)
2. To register for BSC you must have passed
the qualifying exam or be listed as an Math
major.
Presumably, if you have passed the qualifying exam and
are also listed as an Math major, you can still register for
BCS. Therefore, “or” is inclusive.

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Composite Statements
Statements and operators can be combined in any
way to form new statements.

p

q

p

q

(p)(q)

true

true

false

false

false

true

false

false

true

true

false

true

true

false

true

false

false

true

true

true

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Translating English to Logic
I did not buy a lottery ticket this week or I bought a
lottery ticket and won the million dollar on Friday.
Let p and q be two propositions
p: I bought a lottery ticket this week.
q: I won the million dollar on Friday.

In logic form

p(pq)

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Conditional Statements
Implication
Definition: Let p and q be propositions. The conditional
statement p  q, is the proposition “If p, then
q”.
The conditional statement p  q is false when
p is true and q is false and is true otherwise.

where p is called hypothesis, antecedent or premise.
q is called conclusion or consequence

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Implication (if - then)
• Binary Operator, Symbol: 
P

Q

PQ

true

true

true

true

false

false

false

true

true

false

false

true

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Conditional Statements
Biconditional Statements
Definition:

Let p and q be propositions.
biconditional statement pq, is
proposition “p if and only if q”.

The
the

The biconditional (bi-implication) statement p
 q is true when p and q have same truth
values and is false otherwise.

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Biconditional (if and only if)

• Binary Operator, Symbol: 
P

Q

PQ

true

true

true

true

false

false

false

true

false

false

false

true

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Composite Statements
• Statements and operators can be combined in any way to
form new statements.

P

Q

P

Q

(P)(Q)

true

true

false

false

false

true

false

false

true

true

false

true

true

false

true

false

false

true

true

true

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Equivalent Statements
P

Q

(PQ)

(P)(Q)

(PQ)(P)(Q)

true

true

false

false

true

true

false

true

true

true

false

true

true

true

true

false false

true

true

true

• Two statements are called logically equivalent if and only if (iff) they
have identical truth tables
• The statements (PQ) and (P)(Q) are logically equivalent,
because (PQ)(P)(Q) is always true.
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Tautologies and Contradictions
• Tautology is a statement that is always true regardless of the truth
values of the individual logical variables

• Examples:
• R(R)
• (PQ)  (P)(Q)
• If S  T is a tautology, we write S  T.
• If S  T is a tautology, we write S  T.

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Tautologies and Contradictions
• A Contradiction is a statement that is always false regardless of
the truth values of the individual logical variables

Examples
• R(R)
• ((PQ)(P)(Q))
• The negation of any tautology is a contradiction, and
the negation of any contradiction is a tautology.

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Exercises
•We already know the following tautology:
•(PQ)  (P)(Q)

•Nice home exercise:
•Show that (PQ)  (P)(Q).
•These two tautologies are known as De Morgan’s laws.

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Logical Equivalence
Definition
Two proposition form are called logically equivalent if
and only if they have identical truth values for each
possible substitution of propositions for their
proposition variable.

The logical equivalence of proposition forms P
and Q is written

P≡Q
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Equivalence of Two Compound
Propositions P and Q
1. Construct the truth table for P.
2. Construct the truth table for Q using the
same proposition variables for identical
component propositions.
3. Check each combination of truth values of
the proposition variables to see whether the
truth value of P is the same as the truth
value of Q.

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Equivalence Check
a. If in each row the truth value of P is the
same as the truth value of Q, then P and Q
are logically equivalent.
b. If in some row P has a different truth value
from Q, then P and Q are not logically
equivalent.

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Example
• Prove that ¬ (¬p)≡ p
Solution

p
T
F

¬p
F
T

¬ (¬p)
T
F

As you can see the corresponding truth values of p
and ¬ (¬p) are same, hence equivalence is justified.
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Example
Show that the proposition forms ¬(pq) and ¬p  ¬q
are NOT logically equivalent.

p
T
T
F
F

q
T
F
T
F

¬p
F
F
T
T

¬q
F
T
F
T

(pq) ¬(pq) ¬p¬q

T
F
F
F

F
T
T
T

F
F
F
T

Here the corresponding truth values
differ and hence equivalence does
not hold

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De Morgan’s laws
De Morgan’s laws state that:
The negation of an and proposition is
logically equivalent to the or proposition in
which each component is negated.
The negation of an or proposition is logically
equivalent to the and proposition in which
each component is negated.

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Symbolically (De Morgan’s Laws)

1. ¬(pq) ≡ ¬p¬q
2. ¬(pq) ≡ ¬p¬q

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Applying De-Morgan’s Law
Question: Negate the following compound Propositions

1. John is six feet tall and he weights at least 200
pounds.
2. The bus was late or Tom’s watch was slow.

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Solution
a) John is not six feet tall or he weighs less
than 200 pounds.
b) The bus was not late and Tom’s watch was
not slow.

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Inequalities and De Morgan’s Laws
Question Use De Morgan’s laws to write the negation of

-1< x  4
Solution: The given proposition is equivalent to

-1 < x and x  4,
By De Morgan’s laws, the negation is

-1 ≥ x

or

x > 4.

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Tautology and Contradiction
Definition A tautology is a proposition form that is
always true regardless of the truth values of the
individual propositions substituted for its proposition
variables. A proposition whose form is a tautology is
called a tautological proposition.

Definition A contradiction is a proposition form that is
always false regardless of the truth values of the
individual propositions substituted for its proposition
variables. A proposition whose form is a contradiction is
called a contradictory proposition.
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Example
Show that the proposition form p¬p is a
tautology and the proposition form p¬p is a
contradiction.
p

¬p

p ¬p

p ¬p

T

F

T

F

F

T

T

F

Exercise: If t is a tautology and c
contradiction, show that pt≡p and pc≡c?
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Laws of Logic
1. Commutative laws

pq ≡ qp ; pq ≡ qp
2. Associative laws
p  (q  r) ≡ (p q)  r ; p(q r) ≡ (pq)r

3. Distributive laws

p  (q r ) ≡ (p  q)  (p  r)
p  (q  r) ≡ (p  q)  (p  r)
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Laws of Logic
4. Identity laws
p  t ≡ p ; pc ≡ p
5. Negation laws
p¬p ≡ t ; p  ¬p ≡ c
6. Double negation law
¬(¬p) ≡ p
7. Idempotent laws
p  p ≡ p ; pp ≡ p
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Laws of Logic
8. Universal bound laws
pt≡t ;pc≡ c
9. Absorption laws
p (pq) ≡ p ; p (p  q) ≡ p
10. Negation of t and c
¬t ≡ c ; ¬c ≡ t
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Exercise
Using laws of logic, show that

⌐(⌐p  q) (p  q) ≡ p.
Solution
Take ⌐(⌐p  q) (p  q)
≡ (⌐(⌐p)  ⌐q) (p  q), (by De Morgan’s laws)
≡ (p  ⌐q) (p  q),
≡ p (⌐q  q),

(by double negative law)

(by distributive law)
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contd…
≡ p (q  ⌐q), (by the commutative law)
≡ p  c, (by the negation law)
≡ p, (by the identity law)
Skill in simplifying proposition forms is useful in
constructing logically efficient computer programs
and in designing digital circuits.
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Another Example
Prove that ¬[r ∨ (q ∧ (¬r →¬p))] ≡ ¬r ∧ (p∨ ¬q)
¬[r ∨ (q ∧ (¬r → ¬p))]
≡ ¬r ∧ ¬(q ∧ (¬r → ¬p)),
≡ ¬r ∧ ¬(q ∧ (¬¬r ∨ ¬p)),
≡ ¬r ∧ ¬(q ∧ (r ∨¬p)),
≡ ¬r ∧ (¬q ∨ ¬(r ∨ ¬p)),
≡ ¬r ∧ (¬q ∨ (¬r ∧ p)),
≡ (¬r ∧¬q) ∨ (¬r ∧ (¬r ∧ p)),
≡ (¬r ∧¬q) ∨ ((¬r ∧ ¬r) ∧ p),
≡ (¬r ∧¬q) ∨ (¬r ∧ p),
≡ ¬r ∧ (¬q ∨ p),
≡ ¬r ∧ (p ∨¬q),

De Morgan’s law
Conditional rewritten as disjunction
Double negation law
De Morgan’s law
De Morgan’s law, double negation
Distributive law
Associative law
Idempotent law
Distributive law
Commutative law

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Lecture Summery
• Logical Connectives
• Truth Tables
• Compound propositions
• Translating English to logic and logic to English.

• Logical Equivalence
• Equivalence Check
• Tautologies and Contradictions

• Laws of Logic
• Simplification ofDiscrete Structures(CS 335)
Compound Propositions

48

Discrete Structures lecture 2

  • 1.
    Discrete Structures (CS335) Lecture 2 Mohsin Raza University Institute of Information Technology PMAS Arid Agriculture University Rawalpindi
  • 2.
    Compound Propositions Producing newpropositions from existing propositions. Logical Operators or Connectives 1. Not  2. And ˄ 3. Or ˅ 4. Exclusive or  5. Implication  6. Biconditional  Discrete Structures(CS 335) 2
  • 3.
    Compound Propositions Negation ofa proposition Let p be a proposition. The negation of p, denoted by  p (also denoted by ~p), is the statement “It is not the case that p”. The proposition  p is read as “not p”. The truth values of the negation of p,  p, is the opposite of the truth value of p. Discrete Structures(CS 335) 3
  • 4.
    Examples 1. Find thenegation of the following proposition p : Today is Friday. The negation is  p : It is not the case that today is Friday. This negation can be more simply expressed by  p : Today is not Friday. Discrete Structures(CS 335) 4
  • 5.
    Examples 2. Write thenegation of “6 is negative”. The negation is “It is not the case that 6 is negative”. or “6 is nonnegative”. Discrete Structures(CS 335) 5
  • 6.
    Truth Table (NOT) •Unary Operator, Symbol:  p p true false false true Discrete Structures(CS 335) 6
  • 7.
    Conjunction (AND) Definition Let pand q be propositions. The conjunction of p and q, denoted by p˄q, is the proposition “p and q”. The conjunction p˄q is true when p and q are both true and is false otherwise. Discrete Structures(CS 335) 7
  • 8.
    Examples 1. Find theconjunction of the propositions p and q, where p : Today is Friday. q : It is raining today. The conjunction is p˄q : Today is Friday and it is raining today. Discrete Structures(CS 335) 8
  • 9.
    Truth Table (AND) •Binary Operator, Symbol:  p q pq true true true true false false false true false false false false Discrete Structures(CS 335) 9
  • 10.
    Disjunction (OR) Definition Let pand q be propositions. The disjunction of p and q, denoted by p˅q, is the proposition “p or q”. The disjunction p˅q is false when both p and q are false and is true otherwise. Discrete Structures(CS 335) 10
  • 11.
    Examples 1. Find thedisjunction of the propositions p and q, where p : Today is Friday. q : It is raining today. The disjunction is p˅q : Today is Friday or it is raining today. Discrete Structures(CS 335) 11
  • 12.
    Truth Table (OR) •Binary Operator, Symbol:  p q pq true true true true false true false true true false false false Discrete Structures(CS 335) 12
  • 13.
    Exclusive OR (XOR) Definition Letp and q be propositions. The exclusive or of p and q, denoted by pq, is the proposition “pq”. The exclusive or, p  q, is true when exactly one of p and q is true and is false otherwise. Discrete Structures(CS 335) 13
  • 14.
    Examples 1. Find theexclusive or of the propositions p and q, where p : Atif will pass the course CSC102. q : Atif will fail the course CSC102. The exclusive or is pq : Atif will pass or fail the course CSC102. Discrete Structures(CS 335) 14
  • 15.
    Truth Table (XOR) •Binary Operator, Symbol:  p q pq true true false true false true false true true false false false Discrete Structures(CS 335) 15
  • 16.
    Examples (OR vsXOR) The following proposition uses the (English) connective “or”. Determine from the context whether “or” is intended to be used in the inclusive or exclusive sense. 1. “Nabeel has one or two brothers”. A person cannot have both one and two brothers. Therefore, “or” is used in the exclusive sense. Discrete Structures(CS 335) 16
  • 17.
    Examples (OR vsXOR) 2. To register for BSC you must have passed the qualifying exam or be listed as an Math major. Presumably, if you have passed the qualifying exam and are also listed as an Math major, you can still register for BCS. Therefore, “or” is inclusive. Discrete Structures(CS 335) 17
  • 18.
    Composite Statements Statements andoperators can be combined in any way to form new statements. p q p q (p)(q) true true false false false true false false true true false true true false true false false true true true Discrete Structures(CS 335) 18
  • 19.
    Translating English toLogic I did not buy a lottery ticket this week or I bought a lottery ticket and won the million dollar on Friday. Let p and q be two propositions p: I bought a lottery ticket this week. q: I won the million dollar on Friday. In logic form p(pq) Discrete Structures(CS 335) 19
  • 20.
  • 21.
    Conditional Statements Implication Definition: Letp and q be propositions. The conditional statement p  q, is the proposition “If p, then q”. The conditional statement p  q is false when p is true and q is false and is true otherwise. where p is called hypothesis, antecedent or premise. q is called conclusion or consequence Discrete Structures(CS 335) 21
  • 22.
    Implication (if -then) • Binary Operator, Symbol:  P Q PQ true true true true false false false true true false false true Discrete Structures(CS 335) 22
  • 23.
    Conditional Statements Biconditional Statements Definition: Letp and q be propositions. biconditional statement pq, is proposition “p if and only if q”. The the The biconditional (bi-implication) statement p  q is true when p and q have same truth values and is false otherwise. Discrete Structures(CS 335) 23
  • 24.
    Biconditional (if andonly if) • Binary Operator, Symbol:  P Q PQ true true true true false false false true false false false true Discrete Structures(CS 335) 24
  • 25.
    Composite Statements • Statementsand operators can be combined in any way to form new statements. P Q P Q (P)(Q) true true false false false true false false true true false true true false true false false true true true Discrete Structures(CS 335) 25
  • 26.
    Equivalent Statements P Q (PQ) (P)(Q) (PQ)(P)(Q) true true false false true true false true true true false true true true true false false true true true •Two statements are called logically equivalent if and only if (iff) they have identical truth tables • The statements (PQ) and (P)(Q) are logically equivalent, because (PQ)(P)(Q) is always true. Discrete Structures(CS 335) 26
  • 27.
    Tautologies and Contradictions •Tautology is a statement that is always true regardless of the truth values of the individual logical variables • Examples: • R(R) • (PQ)  (P)(Q) • If S  T is a tautology, we write S  T. • If S  T is a tautology, we write S  T. Discrete Structures(CS 335) 27
  • 28.
    Tautologies and Contradictions •A Contradiction is a statement that is always false regardless of the truth values of the individual logical variables Examples • R(R) • ((PQ)(P)(Q)) • The negation of any tautology is a contradiction, and the negation of any contradiction is a tautology. Discrete Structures(CS 335) 28
  • 29.
    Exercises •We already knowthe following tautology: •(PQ)  (P)(Q) •Nice home exercise: •Show that (PQ)  (P)(Q). •These two tautologies are known as De Morgan’s laws. Discrete Structures(CS 335) 29
  • 30.
    Logical Equivalence Definition Two propositionform are called logically equivalent if and only if they have identical truth values for each possible substitution of propositions for their proposition variable. The logical equivalence of proposition forms P and Q is written P≡Q Discrete Structures(CS 335) 30
  • 31.
    Equivalence of TwoCompound Propositions P and Q 1. Construct the truth table for P. 2. Construct the truth table for Q using the same proposition variables for identical component propositions. 3. Check each combination of truth values of the proposition variables to see whether the truth value of P is the same as the truth value of Q. Discrete Structures(CS 335) 31
  • 32.
    Equivalence Check a. Ifin each row the truth value of P is the same as the truth value of Q, then P and Q are logically equivalent. b. If in some row P has a different truth value from Q, then P and Q are not logically equivalent. Discrete Structures(CS 335) 32
  • 33.
    Example • Prove that¬ (¬p)≡ p Solution p T F ¬p F T ¬ (¬p) T F As you can see the corresponding truth values of p and ¬ (¬p) are same, hence equivalence is justified. Discrete Structures(CS 335) 33
  • 34.
    Example Show that theproposition forms ¬(pq) and ¬p  ¬q are NOT logically equivalent. p T T F F q T F T F ¬p F F T T ¬q F T F T (pq) ¬(pq) ¬p¬q T F F F F T T T F F F T Here the corresponding truth values differ and hence equivalence does not hold Discrete Structures(CS 335) 34
  • 35.
    De Morgan’s laws DeMorgan’s laws state that: The negation of an and proposition is logically equivalent to the or proposition in which each component is negated. The negation of an or proposition is logically equivalent to the and proposition in which each component is negated. Discrete Structures(CS 335) 35
  • 36.
    Symbolically (De Morgan’sLaws) 1. ¬(pq) ≡ ¬p¬q 2. ¬(pq) ≡ ¬p¬q Discrete Structures(CS 335) 36
  • 37.
    Applying De-Morgan’s Law Question:Negate the following compound Propositions 1. John is six feet tall and he weights at least 200 pounds. 2. The bus was late or Tom’s watch was slow. Discrete Structures(CS 335) 37
  • 38.
    Solution a) John isnot six feet tall or he weighs less than 200 pounds. b) The bus was not late and Tom’s watch was not slow. Discrete Structures(CS 335) 38
  • 39.
    Inequalities and DeMorgan’s Laws Question Use De Morgan’s laws to write the negation of -1< x  4 Solution: The given proposition is equivalent to -1 < x and x  4, By De Morgan’s laws, the negation is -1 ≥ x or x > 4. Discrete Structures(CS 335) 39
  • 40.
    Tautology and Contradiction DefinitionA tautology is a proposition form that is always true regardless of the truth values of the individual propositions substituted for its proposition variables. A proposition whose form is a tautology is called a tautological proposition. Definition A contradiction is a proposition form that is always false regardless of the truth values of the individual propositions substituted for its proposition variables. A proposition whose form is a contradiction is called a contradictory proposition. Discrete Structures(CS 335) 40
  • 41.
    Example Show that theproposition form p¬p is a tautology and the proposition form p¬p is a contradiction. p ¬p p ¬p p ¬p T F T F F T T F Exercise: If t is a tautology and c contradiction, show that pt≡p and pc≡c? Discrete Structures(CS 335) is 41
  • 42.
    Laws of Logic 1.Commutative laws pq ≡ qp ; pq ≡ qp 2. Associative laws p  (q  r) ≡ (p q)  r ; p(q r) ≡ (pq)r 3. Distributive laws p  (q r ) ≡ (p  q)  (p  r) p  (q  r) ≡ (p  q)  (p  r) Discrete Structures(CS 335) 42
  • 43.
    Laws of Logic 4.Identity laws p  t ≡ p ; pc ≡ p 5. Negation laws p¬p ≡ t ; p  ¬p ≡ c 6. Double negation law ¬(¬p) ≡ p 7. Idempotent laws p  p ≡ p ; pp ≡ p Discrete Structures(CS 335) 43
  • 44.
    Laws of Logic 8.Universal bound laws pt≡t ;pc≡ c 9. Absorption laws p (pq) ≡ p ; p (p  q) ≡ p 10. Negation of t and c ¬t ≡ c ; ¬c ≡ t Discrete Structures(CS 335) 44
  • 45.
    Exercise Using laws oflogic, show that ⌐(⌐p  q) (p  q) ≡ p. Solution Take ⌐(⌐p  q) (p  q) ≡ (⌐(⌐p)  ⌐q) (p  q), (by De Morgan’s laws) ≡ (p  ⌐q) (p  q), ≡ p (⌐q  q), (by double negative law) (by distributive law) Discrete Structures(CS 335) 45
  • 46.
    contd… ≡ p (q ⌐q), (by the commutative law) ≡ p  c, (by the negation law) ≡ p, (by the identity law) Skill in simplifying proposition forms is useful in constructing logically efficient computer programs and in designing digital circuits. Discrete Structures(CS 335) 46
  • 47.
    Another Example Prove that¬[r ∨ (q ∧ (¬r →¬p))] ≡ ¬r ∧ (p∨ ¬q) ¬[r ∨ (q ∧ (¬r → ¬p))] ≡ ¬r ∧ ¬(q ∧ (¬r → ¬p)), ≡ ¬r ∧ ¬(q ∧ (¬¬r ∨ ¬p)), ≡ ¬r ∧ ¬(q ∧ (r ∨¬p)), ≡ ¬r ∧ (¬q ∨ ¬(r ∨ ¬p)), ≡ ¬r ∧ (¬q ∨ (¬r ∧ p)), ≡ (¬r ∧¬q) ∨ (¬r ∧ (¬r ∧ p)), ≡ (¬r ∧¬q) ∨ ((¬r ∧ ¬r) ∧ p), ≡ (¬r ∧¬q) ∨ (¬r ∧ p), ≡ ¬r ∧ (¬q ∨ p), ≡ ¬r ∧ (p ∨¬q), De Morgan’s law Conditional rewritten as disjunction Double negation law De Morgan’s law De Morgan’s law, double negation Distributive law Associative law Idempotent law Distributive law Commutative law Discrete Structures(CS 335) 47
  • 48.
    Lecture Summery • LogicalConnectives • Truth Tables • Compound propositions • Translating English to logic and logic to English. • Logical Equivalence • Equivalence Check • Tautologies and Contradictions • Laws of Logic • Simplification ofDiscrete Structures(CS 335) Compound Propositions 48