已知数据格式,实现一个函数 fn 找出链条中所有的父级 id 题目描述 const list = [{ id: '1', name: 'test1', children: [ { id: '11', name: 'test11', children: [ { id: '111', name: 'test111' }, { id: '112', name: 'test112' } ] }, { id: '12', name: 'test12', children: [ { id: '121', name: 'test121' }, { id: '122', name: 'test122' } ] } ] }]; const id = '112' const fn = (value) => { ... } fn(id, list) // 输出 [1, 11, 112] 代码 function fn(id, list) { const match = list.find(item => item.id === id); if (match) return [id]; const sub = list.find(item => id.startsWith(item.id)); return [sub.id].concat(fn(id, sub.children)); }