[webptmad0418] Rulo - #141
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ta-web-mad
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Dale un repaso a lo que te he comentado, por lo demás, buen trabajo! 👍
| result += hacker1[i].toUpperCase() + " "; | ||
| } | ||
| console.log(result.trim()); | ||
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Buena esa, has usado la función trim( ) 👍
| result += hacker1[i]; | ||
| } | ||
| console.log(result); | ||
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Muy bien, ahora que lo sabes hacer manualmente, prueba con split( ), join( ) y reverse( ) para el último caso
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var hacker1 = 'Tommy';
console.log(hacker1.split("").join(" ").toUpperCase());
console.log(hacker1.split("").reverse().join(""));
mejor??? jeje
| if (palindrome[i] !== palindrome[palength - i -1]) { | ||
| resultado = false; | ||
| } | ||
| } |
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No está mal, pero inténtalo sin usar expresiones regulares. Y además, qué pasaría si te doy una frase que contenga @? Contemplas los casos de los ejemplos propuestos en el ejercicio, sabrías generalizarlo más?
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var palindrome = prompt("Show me your Palindrome");
var valChars = "abcdefghijklmnñopqrstuvwxyz";
palindrome = palindrome.toLowerCase().split("").filter(checkChar);
if (palindrome.join("") === palindrome.reverse().join(""))
console.log("Looks like we got a Palindrome!!");
else
console.log("Have you seen any Palindrome?");
function checkChar(char) {
return valChars.indexOf(char) > 0;
}
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| // Lorem ipsum generator | ||
| var etCount = chiquitum.match(/et/g).length; | ||
| var fistroCount = chiquitum.match(/fistro/g).length; |
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Es correcto también, pero cómo lo harías sin expresiones regulares? Javascript provée de funciones que te resuelven este problema muy fácilmente
| if (palindrome[i] !== palindrome[palength - i -1]) { | ||
| resultado = false; | ||
| } | ||
| } |
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This pull request is closed. Thank you. |
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