std::shared_ptr<T>::operator[]
From cppreference.com
element_type& operator[]( std::ptrdiff_t idx ) const;
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(since C++17) (constexpr since C++26) |
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Returns a reference to the element at specified location idx of the array pointed to by the stored pointer.
When T is not an array type, it is unspecified whether operator[] is declared. If it is declared, it is unspecified what its return type is, except that the declaration is guaranteed to be well-formed.
If the stored pointer is null, the behavior is undefined.
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If |
(until C++26) |
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If
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(since C++26) |
Parameters
| idx | - | the array index |
Return value
get()[idx]
Exceptions
Throws nothing.
Example
Run this code
#include <cstddef>
#include <iostream>
#include <memory>
int main()
{
const std::size_t arr_size = 10;
std::shared_ptr<int[]> pis(new int[10]{0, 1, 2, 3, 4, 5, 6, 7, 8, 9});
for (std::size_t i = 0; i < arr_size; ++i)
std::cout << pis[i] << ' ';
std::cout << '\n';
}
Output:
0 1 2 3 4 5 6 7 8 9
See also
| returns the stored pointer (public member function) |