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605. Can Place Flowers - LeetCode Python/Java/C++/JS/C#/Go/Ruby Solutions

Visit original link: 605. Can Place Flowers - LeetCode Python/Java/C++/JS/C#/Go/Ruby Solutions for a better experience!

LeetCode link: 605. Can Place Flowers, difficulty: Easy.

LeetCode description of "605. Can Place Flowers"

You have a long flowerbed in which some of the plots are planted, and some are not. However, flowers cannot be planted in adjacent plots.

Given an integer array flowerbed containing 0's and 1's, where 0 means empty and 1 means not empty, and an integer n, return true if n new flowers can be planted in the flowerbed without violating the no-adjacent-flowers rule and false otherwise.

[Example 1]

Input: flowerbed = [1,0,0,0,1], n = 1

Output: true

[Example 2]

Input: flowerbed = [1,0,0,0,1], n = 2

Output: false

[Constraints]

  • 1 <= flowerbed.length <= 2 * 10^4
  • flowerbed[i] is 0 or 1.
  • There are no two adjacent flowers in flowerbed.
  • 0 <= n <= flowerbed.length

Intuition

Check each empty plot (0). If both adjacent plots are empty (or boundaries), plant a flower (set to 1) and count. Return true if the final count ≥ n, otherwise false.

Step by Step Solutions

  1. Initialize counter count = 0.
  2. Iterate through each plot:
    • If current is 1, skip.
    • If current is 0 and both adjacent are 0 (or boundaries), plant (1), increment count.
  3. Return count >= n.

Complexity

  • Time complexity: O(N).
  • Space complexity: O(1).

Python

class Solution:
    def canPlaceFlowers(self, flowerbed: List[int], n: int) -> bool:
        count = 0

        for i in range(len(flowerbed)):
            if flowerbed[i] == 1:
                continue

            if (i == 0 or flowerbed[i - 1] == 0) and \
               (i == len(flowerbed) - 1 or flowerbed[i + 1] == 0):
                flowerbed[i] = 1
                count += 1

        return count >= n

Java

class Solution {
    public boolean canPlaceFlowers(int[] flowerbed, int n) {
        int count = 0;

        for (int i = 0; i < flowerbed.length; i++) {
            if (flowerbed[i] == 1) {
                continue;
            }

            if ((i == 0 || flowerbed[i - 1] == 0) && 
                (i == flowerbed.length - 1 || flowerbed[i + 1] == 0)) {
                flowerbed[i] = 1;
                count++;
            }
        }

        return count >= n;
    }
}

C++

class Solution {
public:
    bool canPlaceFlowers(vector<int>& flowerbed, int n) {
        int count = 0;

        for (int i = 0; i < flowerbed.size(); i++) {
            if (flowerbed[i] == 1) {
                continue;
            }

            if ((i == 0 || flowerbed[i - 1] == 0) && 
                (i == flowerbed.size() - 1 || flowerbed[i + 1] == 0)) {
                flowerbed[i] = 1;
                count++;
            }
        }

        return count >= n;
    }
};

JavaScript

var canPlaceFlowers = function(flowerbed, n) {
  let count = 0;

  for (let i = 0; i < flowerbed.length; i++) {
    if (flowerbed[i] === 1) {
      continue;
    }

    if ((i === 0 || flowerbed[i - 1] === 0) && 
      (i === flowerbed.length - 1 || flowerbed[i + 1] === 0)) {
      flowerbed[i] = 1;
      count++;
    }
  }

  return count >= n;  
};

Go

func canPlaceFlowers(flowerbed []int, n int) bool {
    count := 0

    for i := 0; i < len(flowerbed); i++ {
        if flowerbed[i] == 1 {
            continue
        }

        if (i == 0 || flowerbed[i - 1] == 0) && 
           (i == len(flowerbed) - 1 || flowerbed[i + 1] == 0) {
            flowerbed[i] = 1
            count++
        }
    }

    return count >= n
}

C#

public class Solution
{
    public bool CanPlaceFlowers(int[] flowerbed, int n)
    {
        int count = 0;

        for (int i = 0; i < flowerbed.Length; i++)
        {
            if (flowerbed[i] == 1)
            {
                continue;
            }

            if ((i == 0 || flowerbed[i - 1] == 0) && 
                (i == flowerbed.Length - 1 || flowerbed[i + 1] == 0))
                {
                flowerbed[i] = 1;
                count++;
            }
        }

        return count >= n;
    }
}

Ruby

def can_place_flowers(flowerbed, n)
  count = 0

  flowerbed.each_with_index do |plot, i|
    next if plot == 1

    if (i == 0 || flowerbed[i - 1] == 0) && 
       (i == flowerbed.length - 1 || flowerbed[i + 1] == 0)
      flowerbed[i] = 1
      count += 1
    end
  end

  count >= n
end

Other languages

// Welcome to create a PR to complete the code of this language, thanks!

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Original link: 605. Can Place Flowers - LeetCode Python/Java/C++/JS/C#/Go/Ruby Solutions.

GitHub repository: leetcode-python-java.